Hi, Any hints about how to tackle the following problem greatly appreciated:
given three tables: *employee*: id name ... *contract*: id start_date fte100 ... *employee_contract:* id employee_id contract_id An employee can have one or more contracs; they are linked through the employee_contract table. I would like to find a query that returns the contract details for the latest contract for an employee; i've solved a little step of my puzzle and can retrieve the latest contract by doing something like this: employee_id = 10 contr = db( (db.employee.id == employee_id) & (db.employee_contract.contract_id == db.contract.id) & (db.employee_contract.employee_id == db.employee.id) ).select(db.employee.ALL, db.contract.start_date.max()) latest_start_date = contr.contract.start_date.max() but i need also the corresponding contract.fte100 field. Can this be done by using the DAL, or should i construct a loop to find the answer? Best regards, Jaap -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.