It looks like each project has only one photo associated with it -- do you really need a separate folder for each project just to store a single photo? If you are worried about OS performance issues with large numbers of files in a single directory, you should instead do:
Field('photo', 'upload', uploadseparate=True, autodelete=True) web2py will automatically create many sub-folders to divide up the files. Anyway, what you ask is tricky because the record ID is not known until after a record has been inserted, so instead of relying on web2py's built-in upload mechanism, you would have to manually manage the uploads after record insertion. Anthony On Monday, May 25, 2015 at 11:29:54 AM UTC-4, Najtsirk wrote: > > Dear all, > > let's say the model is: > > import os > > db.define_table('project', > Field('title', 'string'), > Field('photo','upload', > uploadfolder=os.path.join(request.folder,'upload/project/'), > autodelete=True)) > > How can I include record.id in the uploadfolder path so a can have > separatesubfolders, like > os.path.join(request.folder,'upload/project/*$record.id > <http://record.id>*'). > > Best, > Kristjan > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.