Sorry. What I wrote is wrong.
Try this ways:
def test1():
id_company = 1
m, cm = db.meeting, db.co_meet
cm.ref_company.default = id_company
cm.ref_company.readable = cm.ref_company.writable = False
cm.ref_meeting.requires = IS_IN_DB(db, m.id ,'%(title)s')
q = cm.ref_company == id_company
q = q & (m.id == cm.ref_meeting)
grid = SQLFORM.grid(q, field_id=cm.id, fields=[m.title])
return locals()
def test2():
id_company = 1
m, cm = db.meeting, db.co_meet
cm.ref_company.default = id_company
cm.ref_company.readable = cm.ref_company.writable = False
cm.ref_meeting.represent = lambda value, row: m[value].title
cm.ref_meeting.requires = IS_IN_DB(db, m.id ,'%(title)s')
q = cm.ref_company == id_company
grid = SQLFORM.grid(q)
return locals()
On Sun, May 31, 2015 at 11:01 AM, Massimiliano <mbelle...@gmail.com> wrote:
>
> m, cm = db.meeting, db.co_meet
> q = m.id == cm.ref_meeting
> q = q & (cm.ref_company == 1)
> grid = SQLFORM.grid(q, field_id=m.id, fields=[m.id, m.title])
>
>
> On Sun, May 31, 2015 at 4:48 AM, Ben Lawrence <benlawr...@gmail.com>
> wrote:
>
>> Both of your answers give a grid of co_meet.
>>
>> What would the query be in SQLFORM.grid such that it would be a grid of
>> db.meeting for one company (not db.co_meet)?
>>
>>
>> On Thursday, May 7, 2015 at 8:26:47 PM UTC-7, 黄祥 wrote:
>>>
>>> had you tried it?
>>> another work around is u can use smartgrid constraints
>>> e.g.
>>> def test():
>>> table = db.co_meet
>>> query = db.co_meet.ref_company == 1 # whatever value that refer to
>>> table company
>>> grid = SQLFORM.smartgrid(table, constraints = dict(co_meet=query) )
>>> return locals()
>>> best regards,
>>> stifan
>>>
>> --
>> Resources:
>> - http://web2py.com
>> - http://web2py.com/book (Documentation)
>> - http://github.com/web2py/web2py (Source code)
>> - https://code.google.com/p/web2py/issues/list (Report Issues)
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>
>
>
> --
> Massimiliano
>
--
Massimiliano
--
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