Hi all, I am using SOAP of web2py. In local system, Web2py automatic generate xmlns:soap="http://192.168.0.194:8000/bts/service_mb/call/soap" in body of xml. 192.168.0.194 is the ip address of my server. Then, I deploy the app on internet and I use SoapUI to connect to my service. But, a problem is appeared. Web2py still generate xmlns:soap="http://192.168.0.194:8000/bts/service_mb/call/soap" in body of xml. So, i cann't connect to my web service. If I edit url manual from 192.168.0.194 to public ip address, I will connect to service normally. I don't want that I must edit URL manual when I need connect to web service. How must I do to expose public ip address in my web service? Thanks!
-- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.