i'm expecting behave like an ajax call similar to this: var jqxhr = $.post(baseUrl() + "default/test", $('form').serialize()) .done(function(data) { ..... })
i'm writing a single page application and don't want to submit for the form in the tradition sense, i want to pass the form via the ajax call On Tuesday, December 8, 2015 at 2:28:45 PM UTC-5, Anthony wrote: > > Why would the form submit because you re-load a component that is *inside* > the form? Your form doesn't have a submit button, nor an action or a > method, and nothing in your JS code executes a submit. How exactly do you > expect it to be submitted? It is not clear what you are trying to achieve. > > Anthony > > On Sunday, December 6, 2015 at 8:50:21 PM UTC-5, Jason Solack wrote: >> >> So in this case i was just wanting to see if the form was submitted when >> reloading the component via: >> >> jQuery('#test_div').get(0).reload() >> >> >> and by printing the request.vars to the terminal i saw that it wasn't. I >> will try your method $.web2py.component and see what results >> >> On Sunday, December 6, 2015 at 8:14:35 PM UTC-5, Anthony wrote: >>> >>> On Sunday, December 6, 2015 at 7:15:04 PM UTC-5, Jason Solack wrote: >>>> >>>> Sorry i'm not clear! I'm trying to break up a reporting site and my >>>> initial idea was to use several LOAD components where in the past i was >>>> using ajax calls. I like the component framework as it seems i can return >>>> HTML templates... it just feels cleaner. >>>> >>>> I have this component within the form, but i could keep all the >>>> components outside the form if that is required to have them passed to >>>> their corresponding controller. >>>> >>>> Another quick question on components. Is there a way to wait for them >>>> to be loaded until called upon or must they be all loaded on the initial >>>> page load? >>>> >>> >>> Still not quite clear what you are trying to do with the form (as it has >>> no action nor submit button). Anyway, you can always manually load and/or >>> reload a component as follows: >>> >>> First, create a div: >>> >>> <div id='mycomponent'></div> >>> >>> Then load a component into the div via: >>> >>> $.web2py.component('{{=URL('controller', 'function.load')}}', >>> 'mycomponent'); >>> >>> Anthony >>> >>> -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.