If Apache could serve the file by itself, without my Web2Py application 
knowing it, it would be perfect!
But I don't know how to configure Apache so that it does not transmit the 
request to wsgihandler.py.

Here is my virtual host file:
<VirtualHost *:80>
       ServerName adomain.com
       ServerAlias www.adomain.com

        WSGIDaemonProcess web2py user=www-data group=www-data 
display-name=%{GROUP}
        WSGIProcessGroup web2py
        WSGIScriptAlias / /home/www-data/web2py-2.10/wsgihandler.py

        <Directory /home/www-data/web2py-2.10>
                AllowOverride None
                Order Allow,Deny
                Deny from all
                <Files wsgihandler.py>
                        Allow from all
                </Files>
        </Directory>

        AliasMatch ^/([^/]+)/static/(.*)            
/home/www-data/web2py-2.10/applications/$1/static/$2
        <Directory /home/www-data/web2py-2.10/applications/*/static/>
                Order Allow,Deny
                Allow from all
        </Directory>

        <Location /admin>
                Deny from all
        </Location>

        <LocationMatch ^/([^/]+)/appadmin>
                Deny from all
        </LocationMatch>
</VirtualHost>

Is it even possible?

Thanks!

Le samedi 23 janvier 2016 16:52:33 UTC+1, Anthony a écrit :
>
> You could configure Apache itself to respond, or you can use web2py's 
> routes.py to route the incoming request to a controller that then returns 
> the requested file.
>
> Anthony
>
> On Saturday, January 23, 2016 at 10:30:52 AM UTC-5, Jean-François Milants 
> wrote:
>>
>> Hi,
>>
>> I would like to get certificates from Let's Encrypt (
>> https://letsencrypt.org/) for my Web2Py applications, but I don't know 
>> how to make it work with Let's Encrypt.
>>
>> I already manage to get a certificate for a PHP application, using the 
>> --webroot method. This method creates a temporary file in 
>> "${webroot-path}/.well-known/acme-challenge" 
>> to check the validity of the domain/server/... Then, the server from Let's 
>> Encrypt do an HTTP GET command on this file.
>>
>> How to do this with Web2Py? How to make Web2Py answer to a request on a 
>> file that is not in a controller/view? 
>>
>> NOTE : my applications runs on Apache2.2, using the WSGI handler.
>>
>> Thanks!
>>
>

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