Rather than using the "fields" argument, to suppress a field in the grid,
just set its "readable" attribute to False (before creating the grid):
db.t1.bb.readable = False
grid = SQLFORM.grid(db.t1)
Anthony
On Tuesday, May 24, 2016 at 8:44:53 AM UTC-4, mweissen wrote:
>
> Let's say I have table with two integer fields and one virtual field:
>
> db.define_table('t1',
> Field('aa','integer'),
> Field('bb','integer'),
> Field.Virtual('ab', lambda row: row.t1.aa+row.t1.bb),
> )
>
>
> The SQLFORM.grid works fine:
>
> def ab():
> grid=SQLFORM.grid(db.t1,
> fields=(db.t1.aa, db.t1.bb, db.t1.ab),
> user_signature=False,
> )
> return locals()
>
>
> But I do not want to show the column bb and I tried:
>
> def ab():
> grid=SQLFORM.grid(db.t1,
> fields=(db.t1.aa, db.t1.ab),
> user_signature=False,
> )
> return locals()
>
>
> and - of course - now I get a "key error", because the virtual field
> cannot access db.t1.bb.
>
> I understand, that the fields parameter decides, which columns should be
> displayed AND which columns could be used in expressions, e.g. in a
> lambda-function. But these columns could be different.
>
> My question:
> How can I use both columns in a function, but without displaying both
> columns in the grid?
>
> Or simple: is it possible to suppress a column in the grid which has been
> selected in the fields parameter?
>
> Regards Martin
>
>
>
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