I was obviously waiting for your reply only. Ok Anthony I got what you said. But how do I get a variable through an ajax call? Ajax only updates a tag id, right? How do I edit this to make it work?
in controller: def index(): return locals() in model: def retimage(): from random import randint i=randint(0,2) return URL('static','images/%d.jpg' %(i)) in view: {{extend 'layout.html'}} <script> window.setInterval(function(){ {{getimage=retimage()}} document.body.style.background-image = url("{{=getimage}}"); }, 500); </script> I am confused on how to get a variable value though ajax calls. Please help me on this. On Monday, June 13, 2016 at 8:46:28 PM UTC+5:30, Anthony wrote: > > You cannot call Python functions on the server from Javascript code > running in the browser. The following line: > > {{getimage=retimage()}} > > will be called exactly once on the server *before *the HTML page is ever > sent to the browser, and it will not result in anything being written into > the Javascript code (if you look at the page source in the browser, you > will see nothing there). > > If you need to retrieve images from the server without reloading the page, > you must use Ajax. > > Anthony > > > On Monday, June 13, 2016 at 5:30:47 AM UTC-4, Emmanuel Dsouza wrote: >> >> CONTROLLER: >> >> def retimage(): >> >> k=["URL('static','images/1.jpg')","URL('static','images/2.jpg')","URL('static','images/3.jpg')"] >> from random import randint >> i=randint(0,2) >> return k[i] >> def index(): >> return locals() >> >> VIEW: >> >> {{extend 'layout.html'}} >> <script> >> window.setInterval(function(){ >> {{getimage=retimage()}} >> document.body.background = url("{{=getimage}}"); >> }, 5000); >> </script> >> >> >> >> How should I correct this? >> > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.