Your code works for me when using curl "http://jcouelier%40gmail.com:<password escaped>@domain:port/URL"
but now when using the browser. So I think the browser is removing the username and password. On Monday, 4 July 2016 08:30:04 UTC-5, Joel Couelier wrote: > > Hello Massimo, > > Just a quick question, have you got the confirmation if sending user + > password directly in the URL is working on basic auth mode? > > I have added the following on my controller : > > if request.function == 'ping': > auth.settings.allow_basic_login = True > > @auth.requires_login() > def ping(): > return dict() > > and i am trying to access this page launching the following URL : > http://jcouelier%40gmail.com:<password escaped>@domain:port/URL > > But i still obtain the login page > > > > > Le jeudi 31 décembre 2009 03:30:40 UTC+1, mdipierro a écrit : >> >> No but >> >> http://user%40mail.com <http://u...@mail.com/>:password@domain:port/url >> >> may work %40 is the @ escaped. You also have to escape the password. >> >> >> On Dec 30, 2009, at 5:26 PM, Alex Fanjul wrote: >> >> http://u...@mail.com:password@domain:port/url >> >> >> -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
