No. You should define the 'user; action only one (for example in default.py) But, you also need the following in the model
auth.settings.login_url = URL(r=request,c='default',f='user/login') auth.settings.on_failed_authorization = URL (r=request,c='default',f='user/on_failed_authorization') so all models know where to find it. On Jul 6, 1:32 pm, Jose <jjac...@gmail.com> wrote: > On 6 jul, 18:16, mdipierro <mdipie...@cs.depaul.edu> wrote:> Not sure I > understand. You need only one > > > > def user (): > > > return dict(form=auth()) > > > If you need to decorate lots of functions with @auth.requires_login(), > > you can do > > > if not request.function in ['index','other_allowed_function'] and not > > auth.is_logged_in(): > > redirect(URL(r=request,f='user/login')) > > I refer to that if I define: > > def user (): > return dict(form=auth()) > > in default.py, I can decorate only the functions of default.py. If I > need to decorate a function in another_controller.py, I cannot do it. > I must define again: > > def user (): > return dict(form=auth()) > > in another_controller.py > > Jose --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "web2py Web Framework" group. To post to this group, send email to web2py@googlegroups.com To unsubscribe from this group, send email to web2py+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/web2py?hl=en -~----------~----~----~----~------~----~------~--~---
