Hello, I have my sqlgrid working but would need a link to a pdf file.I already inserted two links but they are coming from views, so that wasn't a problem.
links = [ dict(header='Link to Orderfile',body=lambda row: A(row.id,_href=URL('bestellungen', orderfile.xml',vars=dict(bestellung_id=row.id)))), dict(header='Link to XML-site',body=lambda row: A(row.id,_href=URL('bestellungen', 'xml_order.xml',vars=dict(bestellung_id=row.id))))] Is there any way to also link to a file that is stored somwhere? I tried request but to no avail. #dict(header='Link to PDF-File',body=lambda row: A(row.id,_href=URL('{}{}{}{}{}{}{}'.format(request.env.web2py_path,'/applications/',request.application,'/static/orders/pdf/','file.pdf',vars=dict(bestellung_id=row.id)))) Thank you, Annika -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.