I have postgres. How would it look for that? On Saturday, November 14, 2020 at 9:03:13 AM UTC-8 valq...@gmail.com wrote:
> Just in case : pydal doesnt support backend specific aggregate functions > > > суббота, 14 ноября 2020 г. в 19:54:35 UTC+3, valq...@gmail.com: > >> There is no db.executesql >> >> суббота, 14 ноября 2020 г. в 19:51:52 UTC+3, alexg...@gmail.com: >> >>> sorry, did not mean direct SQL through db.executesql , meant through DAL >>> >>> On Saturday, November 14, 2020 at 8:23:11 AM UTC-8 valq...@gmail.com >>> wrote: >>> >>>> Assuming sqlite: >>>> person_cnt = >>>> db.PERSON_PROJECT_PRIORITY.person_fk.count().with_alias('person_cnt') >>>> >>>> >>>> prioritySet = db((db.PERSON.id <http://db.person.id/> == >>>> PERSON-PROJECT-PRIORITY.person_fk) & (PROJECT.id == >>>> PERSON-PROJECT-PRIORITY.project_fk)).select( >>>> ..., >>>> person_cnt, >>>> 'GROUP_CONCAT(person.person_name,",") AS person_list' >>>> groupby = db.PERSON-PROJECT-PRIORITY.project_fk, >>>> ) >>>> >>>> суббота, 14 ноября 2020 г. в 09:40:17 UTC+3, alexg...@gmail.com: >>>> >>>>> How to write a statement that counts which projects are the priority >>>>> of most people >>>>> >>>>> PROJECT >>>>> id >>>>> project_name >>>>> >>>>> PERSON >>>>> id >>>>> person_name >>>>> >>>>> PERSON_PROJECT_PRIORITY >>>>> person_fk >>>>> project_fk >>>>> >>>>> prioritySet = db((db.PERSON.id == PERSON-PROJECT-PRIORITY.person_fk) >>>>> & (PROJECT.id == PERSON-PROJECT-PRIORITY.project_fk)).select() >>>>> >>>>> How to sort by count of projects which have priority in order of the >>>>> most persons' priority? >>>>> >>>>> Output looks like this: >>>>> >>>>> Paint-the-house (10) [Means is the top priority for 10 people] >>>>> Plant-a-garden (5) >>>>> Clean-out-garage (2) >>>>> >>>>> If you have additional time, how to write so output looks like: >>>>> >>>>> Paint-the-house (10) Tom, Sue, Tony, Ted, Mary, Fred, Sal, Chris, Ed, >>>>> Sally >>>>> Plant-a-garden (5) Harry, George, Joanne, Tony, Janet >>>>> Clean-out-garage (2) Clyde, Jane >>>>> >>>>> Thanks, >>>>> >>>>> Alex Glaros >>>>> >>>> -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/web2py/13fb5728-3a9a-45e1-aae8-3f467d4fa9b8n%40googlegroups.com.