I have postgres. How would it look for that?

On Saturday, November 14, 2020 at 9:03:13 AM UTC-8 valq...@gmail.com wrote:

> Just in case : pydal doesnt support backend specific aggregate functions
>
>
> суббота, 14 ноября 2020 г. в 19:54:35 UTC+3, valq...@gmail.com: 
>
>> There is no db.executesql
>>
>> суббота, 14 ноября 2020 г. в 19:51:52 UTC+3, alexg...@gmail.com: 
>>
>>> sorry, did not mean direct SQL through db.executesql , meant through DAL
>>>
>>> On Saturday, November 14, 2020 at 8:23:11 AM UTC-8 valq...@gmail.com 
>>> wrote:
>>>
>>>> Assuming sqlite:
>>>> person_cnt = 
>>>> db.PERSON_PROJECT_PRIORITY.person_fk.count().with_alias('person_cnt')
>>>>
>>>>
>>>> prioritySet = db((db.PERSON.id <http://db.person.id/> == 
>>>> PERSON-PROJECT-PRIORITY.person_fk) & (PROJECT.id == 
>>>> PERSON-PROJECT-PRIORITY.project_fk)).select(
>>>> ...,
>>>> person_cnt, 
>>>> 'GROUP_CONCAT(person.person_name,",") AS person_list'
>>>> groupby = db.PERSON-PROJECT-PRIORITY.project_fk, 
>>>> )
>>>>
>>>> суббота, 14 ноября 2020 г. в 09:40:17 UTC+3, alexg...@gmail.com: 
>>>>
>>>>> How to write a statement that counts which projects are the priority 
>>>>> of most people
>>>>>
>>>>> PROJECT
>>>>> id
>>>>> project_name
>>>>>
>>>>> PERSON
>>>>> id
>>>>> person_name
>>>>>
>>>>> PERSON_PROJECT_PRIORITY
>>>>> person_fk
>>>>> project_fk
>>>>>
>>>>> prioritySet = db((db.PERSON.id == PERSON-PROJECT-PRIORITY.person_fk) 
>>>>> & (PROJECT.id == PERSON-PROJECT-PRIORITY.project_fk)).select()
>>>>>
>>>>> How to sort by count of projects which have priority in order of the 
>>>>> most persons' priority?
>>>>>
>>>>> Output looks like this:
>>>>>
>>>>> Paint-the-house (10)  [Means is the top priority for 10 people]
>>>>> Plant-a-garden (5)
>>>>> Clean-out-garage (2)
>>>>>
>>>>> If you have additional time, how to write so output looks like:
>>>>>
>>>>> Paint-the-house (10) Tom, Sue, Tony, Ted, Mary, Fred, Sal, Chris, Ed, 
>>>>> Sally
>>>>> Plant-a-garden   (5) Harry, George, Joanne, Tony, Janet
>>>>> Clean-out-garage (2) Clyde, Jane
>>>>>
>>>>> Thanks,
>>>>>
>>>>> Alex Glaros
>>>>>
>>>>

-- 
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
--- 
You received this message because you are subscribed to the Google Groups 
"web2py-users" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to web2py+unsubscr...@googlegroups.com.
To view this discussion on the web visit 
https://groups.google.com/d/msgid/web2py/13fb5728-3a9a-45e1-aae8-3f467d4fa9b8n%40googlegroups.com.

Reply via email to