The problem is that I do not undestand where curl is putting the
image.
If it is not in request.vars.keys() then curl is not doing a multipart
form submission.
If the file is in request.body that it will not be parsed and stored
in request.vars but this:

request.body.seek(0)
db.videos.file.store(request.body, 'upload.flv')

should work.
Massimo


On Aug 17, 7:25 am, Ian Reinhart Geiser <ian.gei...@gmail.com> wrote:
> I see this when i return request.vars.keys() I get an empty array.
> That seems a little off... doesn't it?  Could it be that I am missing
> a step with respects to reading the request object?
>
> Thanks for your insight so far!
>
> On Aug 17, 3:18 am, mdipierro <mdipie...@cs.depaul.edu> wrote:
>
> > This is the best way of doind it. Can you try add
>
> > print request.vars.keys
> > request.body.seek(0)
>
> > ?
>
> > On Aug 16, 9:56 pm, Ian Reinhart Geiser <ian.gei...@gmail.com> wrote:
>
> > > Right now im doing this but getting errors:
> > > @service.run
> > > def upload_image( camera_uuid ):
> > >     query = (db.cameras.macaddress == camera_uuid )
> > >     camera_id = db(query).select(db.cameras.id)[0]
> > >     db.videos[0]={ 'camera' : camera_id, 'file' : db.videos.file.store
> > > (request.body, 'upload.flv') }
> > >     return True
>
> > > The problem is that its generating 0 size files.  But the file is
> > > correct, and is created in the database correctly.  Did i miss a step?
>
> > > I am using the following curl line:
> > > curl -T 
> > > ~/test.flvhttp://web2py.geiseri.com/HomeCentral/default/call/run/upload_image/c...
>
> > > I feel like im close...
>
> > > On Aug 16, 1:55 pm, mdipierro <mdipie...@cs.depaul.edu> wrote:
>
> > > > Correction. This works but it probaby does not work with upload.
>
> > > > you may need something like
>
> > > > @auth.requires_login()
> > > > def uploadme(): db.mytable.insert(filefield=request.body.read())
>
> > > > On Aug 16, 12:50 pm, mdipierro <mdipie...@cs.depaul.edu> wrote:
>
> > > > > if you have:
>
> > > > > def mycreate(): return dict(form=crud.create(db.mytable))
>
> > > > > you normally call:http://..../mycreatetogettheform.
> > > > > You can also call it with
>
> > > > >http://..../mycreate.json?json=[]
>
> > > > > where [] is a URLencoded JSONencoded dictionary containing the new
> > > > > record. The ".json" instructs web2py not to generate the form but to
> > > > > expect a json input. This is experimental but give it  try. Should
> > > > > work for any page including crud forms.
>
> > > > > Massimo
>
> > > > > On Aug 16, 10:53 am, Ian Reinhart Geiser <ian.gei...@gmail.com> wrote:
>
> > > > > > Greetings, Currently I have a lovely web form that was fairly easy 
> > > > > > to
> > > > > > implement with web2py.  I now also have cron script that is 
> > > > > > uploading
> > > > > > snapshots of an image from a webcam to my website.   What I would 
> > > > > > like
> > > > > > to do is have a service url that I could post my image to and have 
> > > > > > it
> > > > > > automatically be added vs going through the form.
>
> > > > > > From what I can tell is I would have a run REST url and i would read
> > > > > > the request.body object to get the file.  What I am unclear on is 
> > > > > > how
> > > > > > I might put this on the filesystem and the needed links in the
> > > > > > database correctly.  Do I have to roll my own update code vs using 
> > > > > > the
> > > > > > DAL?
>
> > > > > > Thanks in advance!
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