Unfortunately it did not work. Every 'not so detailed item' gets its
own table instead of a table row.
The latest function reads like:
def latest():
response.functionname='Laatste nieuws'
response.image=URL(r=request,c='static',f='init/media/
utilities_1.jpg')
latest=db((db.nieuws.bedrijf==117)&
(db.nieuws.publicatie_datum<=request.now)&\
(db.nieuws.publicatie_datum>=minus_three_months(request.now)))
.select(db.nieuws.ALL,orderby=~db.nieuws.publicatie_datum)
return dict(latest=latest)
Isn't it possible to divide latest into two dictionaries, one with the
first 6 items and the other with the next 18 items.
def latest():
response.functionname='Laatste nieuws'
response.image=URL(r=request,c='static',f='init/media/
utilities_1.jpg')
latest6=db((db.nieuws.bedrijf==117)&
(db.nieuws.publicatie_datum<=request.now)&\
(db.nieuws.publicatie_datum>=minus_three_months(request.now)))
.select(db.nieuws.ALL,orderby=~db.nieuws.publicatie_datum,limitby=
(0,5))
latest18=db((db.nieuws.bedrijf==117)&
(db.nieuws.publicatie_datum<=request.now)&\
(db.nieuws.publicatie_datum>=minus_three_months(request.now)))
.select(db.nieuws.ALL,orderby=~db.nieuws.publicatie_datum,limitby=
(6,23))
return dict(latest6=latest6,latest18=latest18)
Kind regards,
Annet.
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