another option is qset=db() if arg1 == "xyz": qset=qset(db.abc.id > 0) if arg2 == "xyz": qset=qset(db.def.id > 0) qset.select()
On Dec 30, 9:35 pm, vvk <varunk.ap...@gmail.com> wrote: > Sir, > thanks for the post, seems that I've to re-write all my search > functions. > > ---- > varun > > On Dec 31, 12:54 am, mdipierro <mdipie...@cs.depaul.edu> wrote: > > > queries=[] > > if arg1 == "xyz": queries.append(db.abc.id > 0) > > if arg2 == "xyz": queries.append(db.def.id > 0) > > query = reduce(lambda a,b:(a&b),queries) > > > On Dec 30, 12:20 pm, vvk <varunk.ap...@gmail.com> wrote: > > > > How to initialize a NULL query > > > > My query should be ANDed with various tables depending on arguments I > > > receive. > > > > Like: > > > if arg1 == "xyz": > > > query = (db.abc.id > 0) > > > if arg2 == "xyz": > > > query = (db.def.id > 0) & query > > > > In my "second if" condition, if "first if" condition is not executed, > > > error occurs that query is not initialised. How to tackle this ? > > > > On Dec 30, 10:51 pm, mdipierro <mdipie...@cs.depaul.edu> wrote: > > > > > This: > > > > > query = (-1) > > > > > is not a valid query. The fact it works with sqlite is a miracle. > > > > > On Dec 30, 11:43 am, vvk <varunk.ap...@gmail.com> wrote: > > > > > > query = (-1) > > > > > query = (db.somedb.id > 0) & query > > > > > > This querying worked with SQLITE. But it's giving following error with > > > > > postgres: > > > > > > ProgrammingError: argument of AND must be type boolean, not type > > > > > integer > > > > > LINE 1: ...rchase WHERE (purchase.timeofpurchase<='2009-12-29' AND > > > > > -1); > > > > > > i) I think there is problem with type conversions, is there a way > > > > > out ? > > > > > > ii) Is there a way to initialize a NULL query (like query = (-1) I did > > > > > earlier ?) > > -- You received this message because you are subscribed to the Google Groups "web2py-users" group. To post to this group, send email to web...@googlegroups.com. To unsubscribe from this group, send email to web2py+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/web2py?hl=en.
