say you have
db.define_table('myfile',Field('path')) you can create an action like: def serve_myfile(): import os file_id=request.args(0) row=db.myfile[file_id] root_path = '/path/to/root/of/paths/' return response.stream(open(os.path.join(root_path,row.path),'rb')) and call it with http://...../serve_myfile/2 On 26 Mar, 13:08, psikahtik <psikah...@gmail.com> wrote: > Newb question (trying to learn Python and web2py simultaneously). > I've currently got a MySQL database containing records with file paths > to a whole lot of images and scanned files in a deeply nested folder > structure. I just want to build a simple search page to retrieve those > scans. However, I'm unsure as how to go about building the download > link with URL() and the existing download function. I'm guessing I > probably need to write my own download function but I can't find any > examples of this situation. Can anybody point me in the right > direction here? -- You received this message because you are subscribed to the Google Groups "web2py-users" group. To post to this group, send email to web...@googlegroups.com. To unsubscribe from this group, send email to web2py+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/web2py?hl=en.