Was anybody able to resolve this issue?
Julius

V Pondelok, 21. december 2009 o 20:35 -0300, Tito Garrido napísal(a):
> Looks like it just returns 1 result for:
> http://search.twitter.com/search.atom?q=from%3Aweb2py
> 
> strange... but thanks for your answers!
> 
> On Mon, Dec 21, 2009 at 12:33 AM, mr.freeze <nat...@freezable.com>
> wrote:
>         You should be able to search by user with from%3Auser (url
>         encoded
>         'from:user') :
>         http://search.twitter.com/search.json?q=from%
>         3Auser&page=1&rpp=10
>         
>         On Dec 20, 8:03 pm, Tito Garrido <titogarr...@gmail.com>
>         wrote:
>         > I've found this link too but it doesn't work :-/
>         >
>         >
>         >
>         
>         > On Sun, Dec 20, 2009 at 5:45 PM, mdipierro
>         <mdipie...@cs.depaul.edu> wrote:
>         > > based on this it is rpp=10
>         >
>         > >http://apiwiki.twitter.com/Twitter-Search-API-Method%
>         3A-search
>         >
>         > > On Dec 20, 2:28 pm, Tito Garrido <titogarr...@gmail.com>
>         wrote:
>         > > > def get_twits():
>         > > >   user='web2py'
>         > > >   import gluon.tools
>         > > >   import gluon.contrib.simplejson as sj
>         
>         > > >   page = gluon.tools.fetch('http://twitter.com/%
>         s?format=json'%<http://twitter.com/%s?format=json%27%>user)
>         >
>         > > >   tweets=XML(sj.loads(page)['#timeline'])
>         > > >   return dict(tweets=tweets)
>         >
>         > > > I'm wondering how can we limit this query for last 10
>         tweets...
>         >
>         > > > Anybody has a clue?
>         >
>         > > > Thanks!
>         >
>         > > > --
>         >
>         > > > Linux User #387870
>         > > > .........____
>         > > > .... _/_õ|__|
>         > > > ..º[ .-.___.-._| . . . .
>         > > > .__( o)__( o).:_______
>         >
>         > > --
>         >
>         > > You received this message because you are subscribed to
>         the Google Groups
>         > > "web2py-users" group.
>         > > To post to this group, send email to
>         web...@googlegroups.com.
>         > > To unsubscribe from this group, send email to
>         
>         > > web2py+unsubscr...@googlegroups.com<web2py%
>         2bunsubscr...@googlegroups.com>
>         
>         > > .
>         > > For more options, visit this group at
>         > >http://groups.google.com/group/web2py?hl=en.
>         >
>         > --
>         >
>         > Linux User #387870
>         > .........____
>         > .... _/_õ|__|
>         > ..º[ .-.___.-._| . . . .
>         > .__( o)__( o).:_______
>         
>         --
>         
>         You received this message because you are subscribed to the
>         Google Groups "web2py-users" group.
>         To post to this group, send email to web...@googlegroups.com.
>         To unsubscribe from this group, send email to web2py
>         +unsubscr...@googlegroups.com.
>         For more options, visit this group at
>         http://groups.google.com/group/web2py?hl=en.
>         
>         
>         
> 
> 
> 
> -- 
> 
> Linux User #387870
> .........____
> .... _/_õ|__|
> ..º[ .-.___.-._| . . . .
> .__( o)__( o).:_______
> 
> 
> --
> 
> You received this message because you are subscribed to the Google
> Groups "web2py-users" group.
> To post to this group, send email to web...@googlegroups.com.
> To unsubscribe from this group, send email to web2py
> +unsubscr...@googlegroups.com.
> For more options, visit this group at
> http://groups.google.com/group/web2py?hl=en.


Reply via email to