As I know, at least this is manual's bug.
In the mannual, it use
<a href="{{=URL(args=[page+1])}}">next</a>
But, it will raise error, I use this line instead
<a href="{{=URL(r=request, args=[page+1])}}">next</a>
On 8月25日, 上午1時55分, Vidul Petrov <vidul.r...@gmail.com> wrote:
> Not sure if this help, but you may want to take a look at this
> Pagination class:http://packages.python.org/web2py_utils/paginate.html
>
> On Aug 24, 6:37 pm, dlin <dlin...@gmail.com> wrote:
>
> > ref:http://web2py.com/book/default/chapter/12#Pagination
>
> > In following code, there is two problem:
> > 1. The 'next' button always show. And the len(rows) always = 2
> > 2. I don't know how to proper show the {{=rows}} without last row, I
> > want to use the odd row background-color trick.
>
> > I wrote simliar code in default.py
> > -----------------------------------------
> > def listall():
> > if len(request.args): page=int(request.args[0])
> > else: page=0
> > items_per_page=2
> > limitby=(page*items_per_page,(page+1)*items_per_page + 1)
> > words= db().select(db.mytable.ALL, limitby=limitby)
> > cols = [ 'mytable.' + c for c in db.mytable.fields()[1:]]
> > hdrs = dict([(str(c),c.label) for c in db.mytable])
> > rows =SQLTABLE(words,
> > headers = hdrs,
> > columns=cols,
> > truncate=32)
> > rows['_id'] = 'rows'
> > return dict(rows=rows, page=page, items_per_page=items_per_page)
>
> > And the view listall.html:
> > -------------------------------
> > {{extend 'layout.html'}}
> > {{=rows}}
> > page:{{=page}} <br />
> > len(rows):{{=len(rows)}} <br />
>
> > {{if page:}}
> > <a href="{{=URL(r=request, args=[page-1])}}">previous</a>
> > {{pass}}
>
> > {{if len(rows)>=items_per_page:}}
> > <a href="{{=URL(r=request, args=[page+1])}}">next</a>
> > {{pass}}
>
> > <script>jQuery("#rows tr:odd").css("background-color", "#bbbbff");</
> > script>
>
>
