better way:
link = 'http://' + str(request.env.http_host) + URL('show',
args=row.id)
On 26 sep, 06:30, Tom Atkins <minkto...@gmail.com> wrote:
> Thanks for the replies. I worked out what the problem is. The code in the
> book is incorrect. The line:
>
> link = URL('show', args=row.id)
>
> does not produce a full URL. The RSS service does not like this and fails.
>
> If I replace it with:
>
> link = "http://127.0.0.1:8000"; + URL('show', args=row.id)
>
> then it all works fine. I'm sure there is a more elegant way to fix this!
>
> Please update the example code in the book.
>
> Thanks!
>
> On 25 September 2010 19:08, mdipierro <mdipie...@cs.depaul.edu> wrote:
>
>
>
> > it depends on the model. You must have wiki fields and your action
> > must return record in the format described by the book in chapter 3.
>
> > Massimo
>
> > On Sep 25, 12:34 pm, Tom Atkins <minkto...@gmail.com> wrote:
> > > I've just copied and pasted from the online book the wiki application in
> > > chapter 3. It all works great.
>
> > > I've added the function for the rss feed to controller/default.py and if
> > I
> > > go to:
>
> > >http://127.0.0.1:8000/mywiki/default/news
>
> > > I get a nice page showing the wiki entries.
>
> > > However if I go to:
>
> > >http://127.0.0.1:8000/mywiki/default/news.rss
>
> > > I just get a message saying 'no rss'...
>
> > > Am I doing something stupid or is the code in the book wrong /
> > incomplete.
>
> > > Thanks for any help.
