This reads the entire file in ram. Only ok for small files. May be a
vulnerability if anybody can access this service.
On Nov 24, 5:16 pm, António Ramos <ramstei...@gmail.com> wrote:
> i got xmlrpclib to transfer a file from python script to web2py app
>
> Here is my code
> *Python script*
> import xmlrpclib
> server =
> xmlrpclib.ServerProxy('http://127.0.0.1:8000/CrossValidation1/default/call/xmlrpc')
> filepath='c:\\'
> filename='ico.gif'
> filebin = xmlrpclib.Binary(open(filepath+filename).read())
> server.checkflow(filebin,filename)
> *
> and in my default.py controller*
>
> import xmlrpclib
>
> import os
> @service.xmlrpc
> def checkflow(file,name):
> basedir= request.folder.replace('/','')
> f=open(basedir+'\\uploads\\'+name,'wb')
> db.image.insert(file=name)
> f.write(file.data)
> f.close()
> print "ok"
> return name
>
> def call():
> session.forget()
> return service()
> *
> my model*
> *
> *db.define_table('image',
> Field('file','upload'))
>
> Is this a good practice?
>
> 2010/11/24 mdipierro <mdipie...@cs.depaul.edu>
>
> > No
>
> > filename = request.vars.varwithFile.filename or 'filename.txt'
> > stream = request.vars.varwithFile.file or open(filename,'rb')
> > db.photo.insert(file=db.photo.file.store(stream),filename=filename)
>
> > On Nov 24, 3:37 pm, António Ramos <ramstei...@gmail.com> wrote:
> > > but if i want, using the shell, to add and image manually
> > > do i use
> > > db.photo.insert('file'=varwithFile)
> > > ?????
>
> > > *my test model is
> > > db.define_table('photo',
> > > Field('file','upload'))*
>
> > > Best regards
> > > António
>
>
