I am new to both flex and web2py and I am having great difficulty trying to allow flex to simple connect to web2py. I have followed a few threads here and also copied line for line from this tutorial: http://www.web2pyslices.com/main/slices/take_slice/72 and still no solution. I have web2py set up on my windows 7 box and I am using flash builder 4 to set up my flex. Currently i have:
FLEX: --------------------- <?xml version="1.0" encoding="utf-8"?> <mx:Application xmlns:mx="http://www.adobe.com/2006/mxml"; layout="absolute"> <mx:Script> <![CDATA[ import mx.rpc.events.FaultEvent; import mx.rpc.events.ResultEvent; import mx.controls.Alert; private function resultHandler(event:ResultEvent):void { Alert.show(event.result.toString()); } private function faultHandler(event:FaultEvent):void { Alert.show(event.fault.message); } ]]> </mx:Script> <mx:RemoteObject id="amfService" endpoint="http://127.0.0.1:8000/myapp/rpc/call/amfrpc3"; destination="mydomain" showBusyCursor="true"> <mx:method name="test" result="resultHandler(event)" fault="faultHandler(event)"/> </mx:RemoteObject> <mx:Button x="250" y="150" label="Fire" click="amfService.test();"/> </mx:Application> rpc.py ---------------------------------------- from gluon.tools import Service service = Service(globals()) def call(): session.forget() return service() @service.amfrpc3("mydomain") def test(): return "Test!!!" Flex Error: ------------------------------------- faultCode:Client.Error.MessageSend faultString:'Send failed' faultDetail:'Channel.Connect.Failed error NetConnection.Call.Failed: HTTP: Status 400: url: 'http://127.0.0.1:8000/myapp/rpc/call/amfrpc3'' Can anyone explain why I cannot connect with flex. Am I not setting something up that I should be. Any help would be greatly appreciated.
