hi, i've tried to learn from http://web2py.com/book/default/chapter/10#Ajax-Form-Submission, is it possible to edit the ajax form submission?
e.g. === db.py === db = DAL('sqlite://db.db') db.define_table('post', Field('your_message', 'text')) db.post.your_message.requires = IS_NOT_EMPTY() === default.py === def index(): return dict() def new_post(): form = SQLFORM(db.post) if form.accepts(request.vars, formname=None): results = db().select(orderby = ~db.post.id) return DIV(results) elif form.errors: return TABLE(*[TR(k, v) for k, v in form.errors.items()]) === default/index.html === {{extend 'layout.html'}} <div id="target"></div> <form id="myform"> <input name="your_message" id="your_message" /> <input type="submit" /> </form> <script> jQuery('#myform').submit(function() { ajax('{{=URL('new_post')}}', ['your_message'], 'target'); return false; }); </script> i've already tested it and return null, did anyone knows how to do ajax form submission that return the updated list value. thank you so much.