Actually,
I just found solution for my app, again if somebody can provide more
portable solution that would be great?
<a href="{{=URL('app/static/image.file',listing.file[11:13],
listing.file)}}" rel="prettyPhoto[gallery2]">
<img src="{{=URL('app/static/image.file',listing.file[11:13],
listing.file)}}" /> </a>
Cheers
Ivica
On 10 July 2011 00:31, IK <ivicakr...@gmail.com> wrote:
> Hi Massimo,
>
> When "uploadseparate" is set to True, previously mentioned solution
> will not work, at least not for me.
>
> Although, Bruno gave us one suggestion, I would prefer to use explicit
> image location rather than image ID.
>
> To explain:
>
> ###model:
>
> db.define_table("image",
> ...
>
> Field('file',"upload",uploadseparate=True,required=True,uploadfolder=request.folder
> +'static/' ),
> ...
>
>
> ###view
>
> {{url = URL('static',image.file)}}
> {{=A(IMG(_src=url), _href=url)}}
>
>
> This would give invalid file location:
> "
> <a href="app/static/image.file.9197cf1918d6a0fa.
> 6b617374656c61352e6a7067.jpg"><img src="app/static/image.file.
> 9197cf1918d6a0fa.6b617374656c61352e6a7067.jpg" /></a>
> "
> while correct url is
> 127.0.0.1/app/static/image.file/91/image.file.
> 9197cf1918d6a0fa.6b617374656c61352e6a7067.jpg
>
>
> In attempt to find a solution, I was playing with SUBSTR, but I'm not
> getting clean output (I'm not sure if this is good approach, specially
> from portability point of view)
>
>
> ###contr
> ...
> img_folder= db............select(db.image.file [11:13])
> return dict(img_folder=img_folder)
>
> ###view
> {{=img_folder}}
>
>
>
> and output is
> "
> SUBSTR(image.file,12,(14 - 12))
> 91
> "
>
> If you could give me some pointers, that would be greatly appreciated.
>
> Thanks
> IK
>
> On Jun 17, 3:18 pm, Massimo Di Pierro <massimo.dipie...@gmail.com>
> wrote:
> > This is fine:
> >
> > db.define_table('announce',
> > Field('picture','upload',uploadfolder=request.folder+'static/
> > pictures'),
> > )
> >
> > but why do you need an action to download from the static folder? Why
> > not simply use
> >
> > URL('static',record.picture)
> >
> > On Jun 17, 5:56 am, Bruno Rocha <rochacbr...@gmail.com> wrote:
> >
> >
> >
> >
> >
> >
> >
> > > For security reasons, web2py does not expose the 'uploads' folder to
> the
> > > user, this folder can be accessed only by the 'download' function.
> >
> > > The best way is to set the upload path pointing to /static not to
> /upload
> > > and you will have youruploadedfiles to be served as static files,
> > > bypassing download function.
> >
> > > under /static create a folder called 'picture'
> >
> > > *Go to the table definition and do this:*
> >
> > > *<model>*
> > > db.define_table('announce',
> >
> > >
> Field('picture','upload',uploadfolder=request.folder+'static/pictures'),
> > > )
> > > *</model>*
> >
> > > You are saying DAL to store uploades files in to that folder under
> static
> > > and store the ath in the field.
> >
> > > Now in your controller create a function do handle that (different from
> > > download, it is a kind of viewer)
> >
> > > *<controller>*
> > > def viewer():
> > > row = db(db.announce.id
> > > ==request.args(0)).select(db.announce.picture).first()
> > > redirect(URL('static','pictures',args=row.picture))
> > > *</controller>*
> >
> > > *Now you can fo this:*
> >
> > >http://server/app/default/viewer/3#record id
> >
> > > then you got redirected to theimage(no html page)
> >
> > > example:
> http://127.0.0.1:8000/app/static/pictures/announce.picture.aaf5d3f777...
> >
> > > you can always referdirectlyto theimagepath (not using the viewer
> > > function) but you always need to fetch the picture name from db.
> >
> > > Hope it helps.
> >
> > > Should go on the book?
> >
> > > --
> > > Bruno Rocha
> > > [ About me:http://zerp.ly/rochacbruno]
> > > [ Aprenda a programar:http://CursoDePython.com.br]
> >
> > > On Thu, Jun 16, 2011 at 6:09 AM, Vinicius Assef <vinicius...@gmail.com
> >wrote:
> >
> > > > Hi guys.
> >
> > > > I have a table (called anuncio) with an upload field (called foto),
> so
> > > > anuncio.foto is my upload field.
> >
> > > > I'm showing andlinkingit with this piece of code in my view :
> > > > {{url = URL(c='anuncios',f='download', args=['uploads',
> anuncio.foto])}}
> > > > {{=A(IMG(_src=url), _href=url)}}
> >
> > > > My
> > > > /contollers/anuncios.py/download()<http://anuncios.py/download%28%29>function
> > > > is the default, as seen
> > > > below:
> > > > def download():
> > > > return response.download(request,db)
> >
> > > > When user clicks on thisimage, browser shows the download dialog,
> > > > asking him/her where to save theimage.
> > > > But I'd like to simply show theimage, not present the download
> > > > dialog. All these images will be public.
> >
> > > > How I solved it:
> > > > 1) I entered in /myapp/static/images and created a symbolic link
> > > > called 'uploads' pointing to /myapp/uploads.
> > > > 2) In my view, I changed the: {{url = URL(...}} stuff by this: {{url
> =
> > > > URL(c='static', f='images', args=['uploads', anuncio.foto])}}
> >
> > > > I think this isn't the best choice because I'm pointing URL() to a
> > > > fake controller and function, and I'm counting on an external
> > > > resource: a symbolic link in my filesystem.
> >
> > > > How would be the "web2pythonic" way to do this?
> >
> > > > --
> > > > Vinicius Assef.
>
