try replace orderby=t2.name|t3.name
with orderby=t2.name+t3.name On Jan 22, 12:31 pm, Carlos <carlosgali...@gmail.com> wrote: > Hi, > > I have a special case where one table (t1) has 0:1 relationships with two > other semi-identical tabes (t1.linkt2 to t2 table, t1.linkt3 to t3 table), > and I need to generate a list of all t1 rows with some fields from t2 & t3. > > I'm using the "left" select var which works ok. > > db().select( > t1.id, t2.name, t3.name, > left=[ t2.on( t1.linkt2==t2.id ), t3.on( t1.linkt3==t3.id ) ], > orderby=t2.name|t3.name > ) > > But my problem is that I need to order the rows (in the query, not in the > actual rows result) by the common field "name" in tables t2 & t3, but as if > they were concatenated. > > Currently I get all rows first ordered by t2.name and then all rows ordered > by t3.name afterwards (i.e. two orderby groups), which is not what I need. > > I need to somehow "concatenate" t2.name and t3.name and order by that > concatenation. > > My real situation is more complex but I tried to simplify as much as I > could, I hope I explained clearly. > > Is this possible?, how?. > > Thanks!, > > Carlos
