El jueves, 23 de agosto de 2012 15:50:41 UTC+2, Anthony escribió:
>
> Do you have an existing dict and you need to insert it as a record, but 
> also want the record id? In that case, you can do:
>
> id = db.person.insert(**some_dict)
>
> Anthony
>

  Thanks Antony! That works.

 I tried:

 id=db.person.insert(some_dict)...... without the two stars!... Thanks 
again.

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