On Mon, Oct 4, 2010 at 4:23 AM, Leandro Graciá Gil <
[email protected]> wrote:
> In summary, looking at code like this
>>
>> B& b = c->foo();
>> ...
>> b.m();
>>
>> If c->foo() returns a temporary ("return B();"), then it is safe.
>>
>
> Maybe I'm wrong, but are you completely sure about this one? I would say
> that the temporary object created in return B() will cease to exist as soon
> as it returns (just after the constructor finishes).
foo() is returning a temp by value. On the caller side, that value is
copied to a (hidden) temp whose lifetime is the same as the lifetime of |b|,
and then |b| is set to be a reference to that temp.
By contrast, if foo were returning a temp by reference, then the reference
would be invalid on return because the (foo()-scoped) temp it referred to
would be destroyed when foo() exited.
PK
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