Hi, all！
This is my code(get content of dynamic page,load page from local file
system,include all of the resource, and ouput )
class Nam: public QNetworkAccessManager
{
Q_OBJECT
protected:
virtual QNetworkReply* createRequest(Operation op, const QNetworkRequest &
req, QIODevice * outgoingData = 0)
{
QString path;
......//convert the url of req to the path of the resource in the local
file system
QNetworkRequest newReq(req);
QUrl url(path);
newReq.setUrl(url);
return QNetworkAccessManager::createRequest(op, newReq, outgoingData);
}
};
class WebCapture : public QObject
{
Q_OBJECT
public:
WebCapture();
void get();
signals:
void finished();
private slots:
void saveResult(bool ok);
private:
Nam nam;
QWebPage m_page;
};
WebCapture::WebCapture(): QObject()
{
m_page.setNetworkAccessManager(&nam);
connect(&m_page, SIGNAL(loadFinished(bool)), this, SLOT(saveResult(bool)));
}
void WebCapture::get()
{
QString content;
......//read html code from local file system
QUrl url("http://blog.people.com.cn";);//base url of the page
m_page.mainFrame()->setHtml(content, url);
return ;
}
void WebCapture::saveResult(bool ok)
{
if (!ok)
{
emit finished();
return;
}
qDebug() << m_page.mainFrame()->toHtml();
emit finished();
}
int main(int argc, char* argv[])
{
QApplication a(argc, argv);
WebCapture wc;
QObject::connect(&wc, SIGNAL(finished()), QApplication::instance,
SLOT(quit()));
wc.get;
return a.exec();
}
In average,parse a page need 140ms, but 130ms is spend on a.exec(),so, i have
two question:
1) Is there any way to avoid call QApplication::exec(),because it's
time-consuming.
2) When i call a.exec(), does the rendering progress is called??I don't need to
layout this page.
Zhou Peng
[email protected]
2011-03-16 _______________________________________________
webkit-qt mailing list
[email protected]
http://lists.webkit.org/mailman/listinfo.cgi/webkit-qt
