Hi Gavin,
In order to be deployment safe (original or servlet), you need to use
*URL* method to access your resources.
Replace your original method inputStreamForResourceNamed to
pathURLForResourceNamed and open the URL stream via openStream().
---
Kai
On 26-Sep-06, at 2:54 AM, Gavin Eadie wrote:
My app has been doing this successfully for years:
inStream = app.resourceManager
().inputStreamForResourceNamed (fileName, null, null);
but I converted it to a servlet and this no longer works (inStream
is null) ... ideas? .. Gav
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