David,
Compare:
NSMutableArray allBillsOfMaterial = (NSMutableArray)
aBillOfMaterialComponent.valueForKeyPath("part.billsOfMaterial");
NSArray scheduledRoutingBillsOfMaterial = (NSArray)((BillOfMaterial)
aScheduledRouting.valueForKey("routing")).valueForKeyPath
("part.billsOfMaterial");
I think you may be surprised to find that allBillsOfMaterial and
scheduledRoutingBillsOfMaterial are two references to the same array
being returned by valueForKeyPath().
I could be wrong about this, but I don't see any reason why
valueForKey or valueForKeyPath would automatically give you a copy of
the original array. It's my understanding that it will give you a
reference to that original array. How you cast the result is not
going to change the reference handle to the object or give you a new
instance of the array.
On Mar 27, 2007, at 9:41 AM, David Avendasora wrote:
They are in two separate classes. Each are defined from scratch.
Both are defined using key-value coding.
The code that retrieves that filters the array is: (it is located
in one of my core entity classes)
NSMutableArray allBillsOfMaterial = (NSMutableArray)
aBillOfMaterialComponent.valueForKeyPath("part.billsOfMaterial");
log.debug(aBillOfMaterialComponent.valueForKeyPath
("part.partDescription") + " has "+allBillsOfMaterial.count()+" BOM
(s).");
if (allBillsOfMaterial.count() > 1) {
EOQualifier BOMqual = new EOKeyValueQualifier("isDefault",
EOQualifier.QualifierOperatorEqual, new Integer(1));
EOQualifier.filterArrayWithQualifier(allBillsOfMaterial,
BOMqual);
}
The code for the second is located in a web component:
/** @TypeInfo BillOfMaterial */
public NSArray scheduledRoutingBillsOfMaterial()
{
scheduledRoutingBillsOfMaterial = (NSArray)((BillOfMaterial)
aScheduledRouting.valueForKey("routing")).valueForKeyPath
("part.billsOfMaterial");
log.debug("Number of possible routings for " + ((BillOfMaterial)
aScheduledRouting.routing()).part().valueForKey("partDescription")
+": " + scheduledRoutingBillsOfMaterial.count());
return scheduledRoutingBillsOfMaterial;
}
If the first one gets called, the second only returns one row.
Dave
On Mar 27, 2007, at 8:13 AM, Robert Walker wrote:
And you are absolutely sure you have two separate instances of
NSArray and not two references to the same instance?
arr2 = arr1;
vs
arr2 = arr1.immutableClone(); or arr2 = new NSArray(arr1);
I'm sure it's not as simple as what is shown here, but within
whatever complexity you have in your application I would first
check to make sure that you really have two separate instances of
your array.
If possible check either their object id's or check for equal
references with something like:
if (arr1 == arr2) {
// you have two references to the same array
}
On Mar 27, 2007, at 8:40 AM, David Avendasora wrote:
Okay, I have a odd behavior happening.
When I create and insert an object into my default editing
context, and set all the various fields and relationships
everything works just fine, but if I try to retrieve a list of
all the possible objects for one of the relationships (to
populate a pop-up button) all I get is the already selected one
and not all of them. If I let the session expire then look at it
again, the pop-up button has all the objects in it, just as I'd
expect.
In a completely different part of the code, as part of the
creation and population process, I filter a _different_ NSArray
of objects of the same class and it is this filtering that is
causing the problem, BUT it is done in a different class and I'm
filtering a completely different NSArray.
Why would filtering one NSArray of objects cause a different
NSArray of those same objects to be filtered as well??
Dave
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