try
ERXKeyFilter filter =
ERXKeyFilter.filterWithAttributesAndToOneRelationships();
On Dec 20, 2012, at 10:03 AM, gabor raz <[email protected]> wrote:
> Hi,
>
>
> I try to create a REST interface for a application. And my problem know is i
> don't understand how to set relationships.
> I tried it like in the ERRestRouteExample with the updateAction.
>
> ERXKeyFilter filter =
> ERXKeyFilter.filterWithAttributes();
> filter.include( AppointmentRequest.TO_DECLINE_REASON );
>
> AppointmentRequest request = appointmentRequest();
> update( request, filter );
> editingContext().saveChanges();
>
> return response( request, filter );
>
> My JSON data look like this.
> { toDeclineReason:{ oid: 2 } }
>
> But now I got the message back that I have to provide the "Display Name"
> which is a attribute of the entity DeclineReason.
> Is there another way to set the relationships?
>
>
> Gabor
>
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