I think your URL pattern is broken.
When you want to access a URL parameter like ?id=xyz use web.input() not a
URL-pattern (http://webpy.org/cookbook/input).
So in the URLs use:
'/genplots",'genplots',
and in the GET() method of your genplots class use:
url_data=web.input(id="no data") #the "no data" is a default value, if no
id is given
url_id = web.input().id
And if you want to redirect to an url with an parameter use:
raise web.seeother("/genplots"+"?id="+unicode(id_you_want)) #given that
the id is an integer
I hope this helps. If not we could help better if we had more code.
Am Mittwoch, 1. April 2015 22:59:18 UTC+2 schrieb [email protected]:
>
> Hi all,
>
> In my case, I want to display several images according to a id. The url
> may looks like *~/genplots?id=20150401134514*. I wrote "*raise
> web.seeother('/genplots?id=%s' %(idstring))*" with "
> '*/genplots\?id=(\d*)',
> 'genplots*'". But it won't match url correctly and I got error message
> ""HTTP/1.1 GET /genplots" - 404 Not Found" with expected url in the
> browser's address field.
>
> However, if I use encoding "*raise
> web.seeother('/genplots'+'%3Fid%3D'+idstring)*", it shows correct image
> set with message ""HTTP/1.1 GET /genplots?id=20150401134514" - 200 OK".
> But the url in the browser was "~/genplots*%3F*id*%3D*20150401134725"
> rather than "~/genplots?id=20150401134725". Is there a way to fix this
> issue? I searched but didn't find proper example code. Thanks a lot.
>
> Best Regards,
> -Yongzhi
>
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