Will check youre code out. i hope this week.
The problem now is that now always should the form completely be
processed
and other times is should
for example a Submit Link should i think process the form. But a onChange
listener on a DropDownChoice shouldn't
That last one shouldn't be a real submit with validation. Just a submit
to
keep the current editting values.
Maybe I don't understand you right.
However I think currently you can use a JSButton with
defaultFormProcessing = false. JSButton is a server-only component. It
does not get rendered in html and it is only there to receive onSubmit()
notificatons. It can be triggered with the script gotten from
JSButton.getTriggerJavaScript() ie by the DrowDownChoice-onClick.
Christian
johan
On 11/21/05, Christian Essl <[EMAIL PROTECTED]> wrote:
> nice!
Thanks
> what you do in the submit link i want to do in the form itself (so the
> form
> generates a hidden input)
> Then everything in that form, Links, onChange listenerers will/can use
> that
> one to do the form submit but then dispatch the event)
>
> johan
That's much better. Enclosed is the revised code. For demonstration
there
is also a wicket Button (JSButton) you can use to trigger from outside
the
form and which does itself not render anything.
A SubmitLink has now to be inside a JSForm:
JSForm f = new JSForm("linkForm", new CompoundPropertyModel(mod));
f.add(new TextField("value1"));
f.add(new SubmitLink("link1") {
protected void onSubmit() {
System.out.println("Link1 was clicked, value1 is: "
+ mod.getValue1());
};
});
f.add(new SubmitLink("link2") {
protected void onSubmit() {
System.out.println("Link2 was clicked, value1 is: "
+ mod.getValue1());
};
});
Manuel please test this new code.
Christian
--
Christian Essl
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