The AjaxSubmitButton specifically says that it does NOT have to be attached
to a form; from the javadoc
* A button that submits the form via ajax. Since this button takes the form
as
* a constructor argument it does not need to be added to it unlike the
* [EMAIL PROTECTED] Button} component.
However, in practice, this is not the case. I believe it is associated with
the change (1.2-SNAPSHOT -> 1.3-SNAPSHOT) to extend from Button.
What goes wrong? The exception says something to the effect of "Could not
find Form parent for [the button component]" (see the full stacktrace in my
original message way down below); when debugging, it calls the getForm()
method of my button which instead of returning the Form that was supplied to
the Constructor, calls findParent()
As for the test case, I'll see if I can put something together.
Chuck
Johan Compagner wrote:
>
> a button should be in a form (one of its parents)
> or a button should get the form through its constructor.
>
> So what goes wrong exactly?
> Can you have a small test case?
>
> johan
>
>
> On 12/18/06, ChuckDeal <[EMAIL PROTECTED]> wrote:
>>
>>
>> It gets there fine, its this line:
>>
>> if (submit.getForm() == Form.this
>>
>> that is the problem. submit (which is the button) does not belong to a
>> Form, it is supposed to contain a reference to a Form instead. SInce it
>> can't find a Form object for the button it throws an exception
>>
>> throw new WicketRuntimeException("Could not find Form parent for " +
>> this);
>>
>> Thus killing the execution.
>>
>> To Igor:
>> It didn't make a difference when I renamed (wicket:id) the button from
>> "submit" to "submitButton".
>>
>> Chuck
>>
>>
>> Johan Compagner wrote:
>> >
>> > It should work AjaxSubmitButton is a IFormSubmittingComponent component
>> so
>> > this code:
>> >
>> > IFormSubmittingComponent submit =
>> > (IFormSubmittingComponent)getPage().visitChildren(
>> > IFormSubmittingComponent.class, new IVisitor()
>> > {
>> > public Object component(final Component component)
>> > {
>> > // Get button
>> > final IFormSubmittingComponent submit =
>> > (IFormSubmittingComponent)component;
>> >
>> > // Check for button-name or
>> button-name.xrequest
>> > string
>> > if (submit.getForm() == Form.this
>> > && (getRequest().getParameter(
>> > submit.getInputName()) != null || getRequest()
>> >
>> > .getParameter(submit.getInputName()
>> > + ".x") != null))
>> >
>> > should find the ajax button no matter if it is in the page or not
>> > (this is 1.3 code but as far as i know this isn't really changed)
>> >
>> > Frank are you reading with us? I believe you worked on this.
>> >
>> > johan
>> >
>> >
>> > On 12/13/06, ChuckDeal <[EMAIL PROTECTED]> wrote:
>> >>
>> >>
>> >> I have a Page that has a Form with some select boxes in it and,
>> outside
>> >> the
>> >> Form, I have three buttons (submit[AjaxSubmitButton], reset[AjaxLink],
>> >> cancel[AjaxLink]).
>> >>
>> >> In Wicket 1.2.3 (Actually, I have been using the latest 1.2-SNAPSHOT
>> >> releases) The submit button works as advertised and submits the page.
>> >>
>> >> In 1.3-incubating-SNAPSHOT (latest as of 13DEC2006 7am EST), the page
>> >> fails
>> >> with the following exception:
>> >>
>> >> wicket.WicketRuntimeException: Could not find Form parent for
>> >> [MarkupContainer [Component id = submit, page =
>> >> com.csc.aims.issuetracker.wicket.TestSelectionPage, path =
>> >> 0:submit.TestSelectionPage$7, isVisible = true, isVersioned = false]]
>> >> at wicket.markup.html.form.FormComponent.getForm(
>> >> FormComponent.java:409)
>> >> at wicket.markup.html.form.Form$5.component(Form.java:633)
>> >> at wicket.MarkupContainer.visitChildren(MarkupContainer.java
>> :749)
>> >> at wicket.markup.html.form.Form.findSubmittingButton(Form.java
>> >> :624)
>> >> at wicket.markup.html.form.Form.onFormSubmitted(Form.java:333)
>> >> at
>> >> wicket.ajax.form.AjaxFormSubmitBehavior.onEvent(
>> >> AjaxFormSubmitBehavior.java:87)
>> >> at
>> wicket.ajax.AjaxEventBehavior.respond(AjaxEventBehavior.java
>> >> :165)
>> >> at
>> >> wicket.ajax.AbstractDefaultAjaxBehavior.onRequest(
>> >> AbstractDefaultAjaxBehavior.java:225)
>> >> at
>> >>
>> >>
>> wicket.request.target.component.listener.BehaviorRequestTarget.processEvents
>> >> (BehaviorRequestTarget.java:98)
>> >> at
>> >> wicket.request.compound.DefaultEventProcessorStrategy.processEvents(
>> >> DefaultEventProcessorStrategy.java:64)
>> >> at
>> >>
>> >>
>> wicket.request.compound.AbstractCompoundRequestCycleProcessor.processEvents
>> >> (AbstractCompoundRequestCycleProcessor.java:56)
>> >> at
>> >> wicket.RequestCycle.doProcessEventsAndRespond(RequestCycle.java
>> >> :912)
>> >> at wicket.RequestCycle.processEventsAndRespond(
>> RequestCycle.java
>> >> :950)
>> >> at wicket.RequestCycle.step(RequestCycle.java:1026)
>> >> at wicket.RequestCycle.steps(RequestCycle.java:1100)
>> >> at wicket.RequestCycle.request(RequestCycle.java:454)
>> >> at wicket.protocol.http.WicketFilter.doGet(WicketFilter.java
>> :243)
>> >> at
>> wicket.protocol.http.WicketFilter.doFilter(WicketFilter.java
>> >> :122)
>> >>
>> >> After consulting the Migration Wiki Page
>> >> (http://cwiki.apache.org/WICKET/migrate-13.html) it shows that both
>> >> AjaxSubmitButton and AjaxSubmitLink have changed to extend Button.
>> >> (Actually, I checked AjaxSubmitLink and it does NOT extend
>> >> button...). But
>> >> according to the javadoc for AjaxSubmitButton, since you pass a form
>> to
>> >> the
>> >> constructor, you don't need to add the component to a Form object. In
>> >> practice this was not true. Once I added the button to the form, it
>> >> worked
>> >> as advertised.
>> >>
>> >> I'm guessing the change was necessary as a result of the hierarchy
>> change
>> >> of
>> >> AjaxSubmitButton, but maybe the Form arg is no longer needed since you
>> >> must
>> >> add it to the Form object?
>> >>
>> >> Chuck
>> >> --
>> >> View this message in context:
>> >>
>> http://www.nabble.com/AjaxSubmitButton-and-not-adding-it-to-a-Form-tf2815470.html#a7857386
>> >> Sent from the Wicket - User mailing list archive at Nabble.com.
>> >>
>> >>
>> >>
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