One question is why does the code print? 0 EIGENVALUES BELOW THE ENERGY -12.20000 ******************************************************** i.e. that there are no eigenvalues more than 3Ry below the core separation energy?
At the bottom of case. scfup I obtain: Most likely no ghostbands, but adjust Energy-parameters or use -in1ef / -in1new :WARN : QTL-B value eq. 4.97 in Band of energy -8.32610 ATOM= 134 L= 0 :WARN : You should change the E-parameter in case.in1 or use -in1ef / -in1new switch QTL-B VALUE .EQ. 5.47621 in Band of energy -8.32606 ATOM= 134 L= 0 However, from case.outputst I would have thought that the L=0 states of this phosphorus atom would be in the core? I have attempted adjusting the El parameters in case. in1 to adjust to this band energy, but the problem returns at a slightly difference band energy. In case.in1 for phosphorus I have used: 0.30 4 0 (GLOBAL E-PARAMETER WITH n OTHER CHOICES, global APW/LAPW) 1 0.30 0.000 CONT 1 1 -8.80 0.001 STOP 1 0 -0.79 0.002 CONT 1 0 -10.5 0.000 CONT 1 The default for the L=0 LO was 0.3. Any help as to whether these s-states are real or how to describe them would be very helpful. Many thanks, David Tompsett. --0015175cb5083f48d6049de4b11f Content-Type: text/html; charset=ISO-8859-1 Content-Transfer-Encoding: quoted-printable Dear All,<br><br>I am performing calculations on slabs of the material LiFe= PO4 using GGA+U in the latest Wien2k release. <br><br>To perform min_lapw internal parameter optimisation I reduce the RMT's an= d use R=3D1.06 for Phosphorus. This results in a need to reduce the default for energy separation of core states to -9.2Ry during lstart. As a=20 result Phosphorus 2p states become part of the valence and need to be=20 treated by a LO. I am having trouble with large QTL-B values regarding=20 the L=3D0 states though.<br> <br>The energy parameters for phosphorus from case.outputst are:<br><br>=A0= =A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0 P=A0=A0=A0=A0=A0=A0= =A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0= =A0=A0=A0 RHFS<br><br>=A0=A0=A0=A0=A0=A0=A0=A0 OCCUPANCY=A0=A0=A0 ENERGY(RY= D)=A0=A0=A0=A0=A0=A0=A0=A0 (R4)=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0 (R2)= =A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0 (R)=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0= =A0=A0=A0=A0 (R-1)=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0 (R-3)<br> <br>=A0 1S=A0=A0=A0=A0=A0 1.000=A0=A0=A0 -1.5314154E+02=A0=A0=A0=A0 5.40205= 20E-04=A0=A0=A0=A0 1.4448157E-02=A0=A0=A0=A0 1.0359168E-01=A0=A0=A0=A0 1.46= 48276E+01<br>=A0 1S=A0=A0=A0=A0=A0 1.000=A0=A0=A0 -1.5311976E+02=A0=A0=A0= =A0 5.3994095E-04=A0=A0=A0=A0 1.4444579E-02=A0=A0=A0=A0 1.0357948E-01=A0=A0= =A0=A0 1.4649640E+01<br> =A0 2S=A0=A0=A0=A0=A0 1.000=A0=A0=A0 -1.2760822E+01=A0=A0=A0=A0 1.9082408E-= 01=A0=A0=A0=A0 3.2223815E-01=A0=A0=A0=A0 5.1970457E-01=A0=A0=A0=A0 2.824795= 1E+00<br>=A0 2S=A0=A0=A0=A0=A0 1.000=A0=A0=A0 -1.2738260E+01=A0=A0=A0=A0 1.= 8994048E-01=A0=A0=A0=A0 3.2198220E-01=A0=A0=A0=A0 5.1963797E-01=A0=A0=A0=A0= 2.8236582E+00<br>=A0 2P*=A0=A0=A0=A0 1.000=A0=A0=A0 -9.1715513E+00=A0=A0= =A0=A0 1.9086915E-01=A0=A0=A0=A0 2.9430623E-01=A0=A0=A0=A0 4.8389989E-01=A0= =A0=A0=A0 2.7216785E+00<br> =A0 2P*=A0=A0=A0=A0 1.000=A0=A0=A0 -9.1408359E+00=A0=A0=A0=A0 1.8923948E-01= =A0=A0=A0=A0 2.9388805E-01=A0=A0=A0=A0 4.8380643E-01=A0=A0=A0=A0 2.7206626E= +00<br>=A0 2P=A0=A0=A0=A0=A0 2.000=A0=A0=A0 -9.1041258E+00=A0=A0=A0=A0 1.94= 05529E-01=A0=A0=A0=A0 2.9690219E-01=A0=A0=A0=A0 4.8614968E-01=A0=A0=A0=A0 2= .7052889E+00=A0=A0=A0=A0 6.2902446E+01<br> =A0 2P=A0=A0=A0=A0=A0 2.000=A0=A0=A0 -9.0735022E+00=A0=A0=A0=A0 1.9234866E-= 01=A0=A0=A0=A0 2.9645480E-01=A0=A0=A0=A0 4.8603999E-01=A0=A0=A0=A0 2.704322= 7E+00=A0=A0=A0=A0 6.2822412E+01<br>=A0 3S=A0=A0=A0=A0=A0 1.000=A0=A0=A0 -1.= 0878541E+00=A0=A0=A0=A0 2.9229783E+01=A0=A0=A0=A0 4.1553776E+00=A0=A0=A0=A0= 1.8919617E+00=A0=A0=A0=A0 7.2068651E-01<br> =A0 3S=A0=A0=A0=A0=A0 1.000=A0=A0=A0 -8.8775170E-01=A0=A0=A0=A0 3.1604015E+= 01=A0=A0=A0=A0 4.2438626E+00=A0=A0=A0=A0 1.9036101E+00=A0=A0=A0=A0 7.240207= 9E-01<br>=A0 3P*=A0=A0=A0=A0 1.000=A0=A0=A0 -4.6442261E-01=A0=A0=A0=A0 7.94= 15784E+01=A0=A0=A0=A0 6.4475288E+00=A0=A0=A0=A0 2.3215625E+00=A0=A0=A0=A0 5= .8248088E-01<br>=A0 3P*=A0=A0=A0=A0 0.000=A0=A0=A0 -2.7621315E-01=A0=A0=A0= =A0 1.1443191E+02=A0=A0=A0=A0 7.4136855E+00=A0=A0=A0=A0 2.4614687E+00=A0=A0= =A0=A0 5.6064252E-01<br> =A0 3P=A0=A0=A0=A0=A0 2.000=A0=A0=A0 -4.6042138E-01=A0=A0=A0=A0 8.0649286E+= 01=A0=A0=A0=A0 6.4959005E+00=A0=A0=A0=A0 2.3301759E+00=A0=A0=A0=A0 5.800522= 7E-01=A0=A0=A0=A0 3.7773200E+00<br>=A0 3P=A0=A0=A0=A0=A0 0.000=A0=A0=A0 -2.= 7242986E-01=A0=A0=A0=A0 1.1708022E+02=A0=A0=A0=A0 7.4892061E+00=A0=A0=A0=A0= 2.4735418E+00=A0=A0=A0=A0 5.5768379E-01=A0=A0=A0=A0 3.5655831E+00<br> <br>Examples of the low lying states I find in case.output1up and case.outp= ut1dn are:<br>From up:<br>=A0=A0=A0=A0 K=3D=A0=A0 0.25000=A0=A0 0.50000=A0= =A0 0.50000=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0 1<br>=A0=A0=A0=A0=A0 MATRIX SI= ZE 9192=A0 WEIGHT=3D 2.00=A0 PGR:<br>=A0=A0=A0=A0 EIGENVALUES ARE:<br> =A0=A0=A0 -11.4326572=A0 -11.4326443=A0 -11.4304960=A0 -11.4304836=A0 -11.3= 548181<br>=A0=A0=A0 -11.3548178=A0 -11.3547956=A0 -11.3547954=A0=A0 -7.8222= 277=A0=A0 -7.8221979<br>=A0=A0=A0=A0 -7.8198177=A0=A0 -7.8197860=A0=A0 -7.8= 139864=A0=A0 -7.8138903=A0=A0 -7.8117306<br>=A0=A0=A0=A0 -7.8116318=A0=A0 -= 7.8093135=A0=A0 -7.8092692=A0=A0 -7.8073401=A0=A0 -7.8073004<br> =A0=A0=A0=A0 -7.7374667=A0=A0 -7.7374653=A0=A0 -7.7373719=A0=A0 -7.7373716= =A0=A0 -7.7338651<br>=A0=A0=A0=A0 -7.7338636=A0=A0 -7.7337751=A0=A0 -7.7337= 738=A0=A0 -7.7332502=A0=A0 -7.7332486<br>=A0=A0=A0=A0 -7.7329941=A0=A0 -7.7= 329924=A0=A0 -5.4113446=A0=A0 -5.4113297=A0=A0 -5.4091455<br>=A0=A0=A0=A0 -= 5.4091305=A0=A0 -5.3250955=A0=A0 -5.3250950=A0=A0 -5.3250626=A0=A0 -5.32506= 22<br> <br>From dn:<br>=A0=A0=A0=A0 K=3D=A0=A0 0.12500=A0=A0 0.25000=A0=A0 0.50000= =A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0 1<br>=A0=A0=A0=A0=A0 MATRIX SIZE 4988=A0 = WEIGHT=3D 2.00=A0 PGR:<br>=A0=A0=A0=A0 EIGENVALUES ARE:<br>=A0=A0=A0=A0 -8.= 5813282=A0=A0 -8.5812344=A0=A0 -8.5638097=A0=A0 -8.5637104=A0=A0 -8.3260488= <br>=A0=A0=A0=A0 -8.3257490=A0=A0 -8.3242101=A0=A0 -8.3239949=A0=A0 -5.6312= 550=A0=A0 -5.6309409<br> =A0=A0=A0=A0 -5.6112020=A0=A0 -5.6109385=A0=A0 -5.6107774=A0=A0 -5.6105375= =A0=A0 -5.6015340<br>=A0=A0=A0=A0 -5.6014578=A0=A0 -4.8776979=A0=A0 -4.8773= 081=A0=A0 -4.8649380=A0=A0 -4.8645429<br>=A0=A0=A0=A0 -4.8612661=A0=A0 -4.8= 609989=A0=A0 -4.8603466=A0=A0 -4.8597815=A0=A0 -4.8473038<br>=A0=A0=A0=A0 -= 4.8470997=A0=A0 -4.8453215=A0=A0 -4.8450239=A0=A0 -4.6260569=A0=A0 -4.62548= 83<br> =A0=A0=A0=A0 -4.6248374=A0=A0 -4.6245754=A0=A0 -4.6239155=A0=A0 -4.6237133= =A0=A0 -4.6234791<br>=A0=A0=A0=A0 -4.6230319=A0=A0 -4.6227243=A0=A0 -4.6219= 883=A0=A0 -4.6218599=A0=A0 -4.6214088<br><br>One question is why does the c= ode print?<br>=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0=A0 0 EIGENVALUES BELOW THE ENE= RGY=A0 -12.20000<br> =A0=A0=A0=A0=A0=A0 ********************************************************= <br>i.e. that there are no eigenvalues more than 3Ry below the core separat= ion energy?<br><br>At the bottom of case. scfup I obtain:<br><br>=A0=A0=A0 = Most likely no ghostbands, but adjust Energy-parameters or use -in1ef / -in= 1new<br> <br><br>:WARN : QTL-B value eq.=A0=A0 4.97=A0 in Band of energy=A0 -8.32610= =A0=A0 ATOM=3D=A0 134=A0=A0 L=3D=A0 0<br>:WARN : You should change the E-pa= rameter in case.in1 or use -in1ef / -in1new switch<br><br><br><br>=A0=A0 QT= L-B VALUE .EQ.=A0=A0=A0 5.47621=A0=A0 in Band of energy=A0=A0 -8.32606=A0= =A0 ATOM=3D=A0 134=A0=A0 L=3D=A0 0<br> <br>However, from case.outputst I would have thought that the L=3D0 states = of this phosphorus atom would be in the core? I have attempted adjusting th= e El parameters in case. in1 to adjust to this band energy, but the problem= returns at a slightly difference band energy.<br clear=3D"all"> <br>In case.in1 for phosphorus I have used:<br>=A0 0.30=A0=A0=A0 4=A0 0=A0= =A0=A0=A0=A0 (GLOBAL E-PARAMETER WITH n OTHER CHOICES, global APW/LAPW)<br>= =A01=A0=A0=A0 0.30=A0=A0=A0=A0=A0 0.000 CONT 1<br>=A01=A0=A0 -8.80=A0=A0=A0= =A0=A0 0.001 STOP 1<br>=A00=A0=A0 -0.79=A0=A0=A0=A0=A0 0.002 CONT 1<br> =A00=A0=A0 -10.5=A0=A0=A0=A0=A0 0.000 CONT 1<br><br>The default for the L= =3D0 LO was 0.3.<br><br>Any help as to whether these s-states are real or h= ow to describe them would be very helpful.<br><br>Many thanks,<br>David Tom= psett.<br> --0015175cb5083f48d6049de4b11f--