On page 73 in the UG, it is outputM (with a capital M). This is different from the outputm (with a lower case m) in your email.

Like bcc Cr, you should not use min_lapw on the TiC usersguide example as it has "fixed" atomic positions at (0,0,0) and (0.5,0.5,0.5) [ http://www.mail-archive.com/wien%40zeus.theochem.tuwien.ac.at/msg00864.html ]. min_lapw is for structures with "free" atomic positions like O (x,x,0) in the TiO2 example [ http://www.wien2k.at/reg_user/textbooks/WIEN2k_lecture-notes_2013/WIEN2k-getting_started.pdf (slide 5) ].

Prof. L. Marks can probably better answer your mixer questions (about ESX, EKIN, ... ).

EKIN is likely a kinetic energy and ESUM is likely a sum of energies. I don't know what ESX stands for.

I think the two numbers next to OCC are probably because one is for spin up and the other is for spin down.

On 9/4/2015 8:38 AM, Dr. K. C. Bhamu wrote:
Dear Gavin Abo
I satisfied with your previous reply but just for query I have another question.

I checked TiC.outputm file as mentioned on page no 73 of UG for grep......WARN.
its shows

root@lenovopc:~/wien_work/excercise/TiC# grep :WARN TiC.outputm

 :WARN : Iteration           13 occurs more than once in this scf file!!!

Is it a sign of any problem?

What is meaning of ESX, EKIN, ESUM in this file (I can guess these are some energies)? Why OCC is double printed like for Ti(J=1) OCC= 2.0000000000E+00 2.0000000000E+00 ??

I scratched mailing list and UG but did not find.

 :WARN : Iteration           13 occurs more than once in this scf file!!!
 JATOM =            1   J =            1
  ESX  =  -7.1323412414E+02 OCC = 2.0000000000E+00  2.0000000000E+00
   ESUM,EKIN =   -767.695848954000 0.000000000000000E+000
 JATOM =            1   J =            2
  ESX  =  -7.6610929538E+01 OCC = 2.0000000000E+00  2.0000000000E+00
   ESUM,EKIN =   -1480.92997309200 0.000000000000000E+000
 JATOM =            1   J =            3
  ESX  =  -6.3548252810E+01 OCC = 2.0000000000E+00  2.0000000000E+00
   ESUM,EKIN =   -1557.54090263000 0.000000000000000E+000
 JATOM =            1   J =            4
  ESX  =  -1.2540010918E+02 OCC = 4.0000000000E+00  4.0000000000E+00
   ESUM,EKIN =   -1621.08915544000 0.000000000000000E+000
 JATOM =            2   J =            1
  ESX  =  -3.7471061572E+01 OCC = 2.0000000000E+00  2.0000000000E+00
   ESUM,EKIN =   -1746.48926462400 0.000000000000000E+000
   ESUM =   -1783.96032619600
 13. ITERATION

Sincerely
Bhamu
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