In the BaTiO3 tutorial, lambda1.struct and lambda0.struct both have spacegroup 99_P4mm and 8 symmetry operations [
https://github.com/spichardo/BerryPI/wiki/Tutorial-1:-Spontaneous-Polarization-in-BaTiO3 ].
I see a sentence in the tutorial:
The symmetry operations are identical (!) to the lambda1 case, in spite of a higher symmetry of the lambda0 structure.
Perhaps that is the sentence that another user got that the symmetry might need to remain the same [
https://www.mail-archive.com/wien@zeus.theochem.tuwien.ac.at/msg16112.html ].
The tet1.struct has spacegroup 99_P4mm, while cubic.struct has spacegroup 221_Pm3m.
According to the tutorial:
8. Spontaneous polarization is obtained by taking a difference in polarization between P(lambda1) and P(lambda0) -> Difference between tet1 and cubic for the PbTiO3 case?
For PbTiO3, is it okay that there are "8 NUMBER OF SYMMETRY OPERATIONS" in cubic.struct and "48 NUMBER OF SYMMETRY OPERATIONS" in tet1.struct for the spontaneous polarization calculation?
On 5/7/2018 4:36 AM, Lokanath Patra wrote:
Dear Oleg,
I am attaching the structure files which I have used for the calculation. I have used similar procedure as given for BaTiO3 tutorial (same parameters for initialising and same k-point mesh for Berrypi. The calculated polarisation for cubic phase is very
low. So so spontaneous polarisation is still very low as given in my previous mail. I am unable to trace my mistakes.
Best regards
Lokanath
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