You did not read up to the end (Graphite with a strong directional dependence 
of the conductivity was an example, maybe it was not lucky to place it in front)
a little later you find:
"In some cases you have to check whether there might be an overlapp of the 
valence and and conduction bands at different k-points, resulting in a 
semimetallic or zero-bandgap type behavior."
and that is (for a semi-metal) the situation you find as C in Wikipedia, isn't 
it ?

By the way, the definition of semi-metals changed with time one just need to 
follow the textbooks in chemistry and physics
see also about metalloids (https://en.wikipedia.org/wiki/Metalloid) .

Ciao
Gerhard

DEEP THOUGHT in D. Adams; Hitchhikers Guide to the Galaxy:
"I think the problem, to be quite honest with you,
is that you have never actually known what the question is."

====================================
Dr. Gerhard H. Fecher
Institut of Inorganic and Analytical Chemistry
Johannes Gutenberg - University
55099 Mainz
and
Max Planck Institute for Chemical Physics of Solids
01187 Dresden
________________________________________
Von: Wien [[email protected]] im Auftrag von Karel 
Vyborny [[email protected]]
Gesendet: Mittwoch, 30. Januar 2019 09:08
An: A Mailing list for WIEN2k users
Betreff: Re: [Wien] Metal or semimetal

A quick question to add my bit into this conversation: where does the
definition of semimetal as "insulating (semiconducting) in one direction
and conducting in another one" come from? I have never heard of this; it
may the lack of my knowledge but I hold that it's the overlaping valence
and conduction bands that define semimetals (and indeed, bismuth has
always been the prime example for me). The strong anisotropy in
conductivity may be a concomitant feature, however, it is not necessary.

Cheers,

Karel


--- x ---
dr. Karel Vyborny
Fyzikalni ustav AV CR, v.v.i.
Cukrovarnicka 10
Praha 6, CZ-16253
tel: +420220318459


On Tue, 29 Jan 2019, Fecher, Gerhard wrote:

> Thank you for the Link, but I don't understand your remarks
> Wikipedia tells:
> - Schematic
> C) a semimetal (like tin (Sn) or graphite and the alkaline earth metals).
> and further
> - Classic semimetals
> The classic semimetallic elements are arsenic, antimony, bismuth, ?-tin (gray 
> tin) and graphite, an allotrope of carbon.
>
> on the page https://en.wikipedia.org/wiki/Graphite one finds
> Graphite has a layered, planar structure. The individual layers are called 
> graphene. ...
> Atoms in the plane are bonded covalently, with only three of the four 
> potential bonding sites satisfied. The fourth electron is free to migrate in 
> the plane, making graphite electrically conductive.
> However, it does not conduct in a direction at right angles to the plane.
>
> Maybe check the band structures of Graphite and Bi to find out what is common 
> and what is different.
>
> You did not understand the remark on the integration of the density of 
> states, please read it correctly.
> The initial question was on the Fermi energy beeing slightly below the top of 
> the valence band
> and this might be caused by a bad integration which depends on the number of 
> k-points (indeed among others)
> and is used to find the Fermi energy.
>
> PS.: Please check the definition of the density of states and you see why 
> flat (say better narrow) bands result in a high density of states and steep 
> ones in a low density of states.
> (that a band is horizontal at a certain point of the Brillouin zone does not 
> mean that the complete band is flat, this situation you have always at the 
> bottom of a parabola) .
>
> Ciao
> Gerhard
>
> DEEP THOUGHT in D. Adams; Hitchhikers Guide to the Galaxy:
> "I think the problem, to be quite honest with you,
> is that you have never actually known what the question is."
>
> ====================================
> Dr. Gerhard H. Fecher
> Institut of Inorganic and Analytical Chemistry
> Johannes Gutenberg - University
> 55099 Mainz
> and
> Max Planck Institute for Chemical Physics of Solids
> 01187 Dresden
> ________________________________________
> Von: Wien [[email protected]] im Auftrag von delamora 
> [[email protected]]
> Gesendet: Dienstag, 29. Januar 2019 19:43
> An: A Mailing list for WIEN2k users
> Betreff: [Wien] Metal or semimetal
>
> I strongly disagree
>
> Wikipedia gives a very different definition
>
> https://en.wikipedia.org/wiki/Semimetal
>
> Bi would be a good example; it has a very low DOS at Ef (with the wikipedia 
> definition of semimetal)
>
> Graphite is conductor in the ab plane and a poor conductor (not insulating) 
> in the c direction
>
> As I said, the bands are flat near the band edge, so it would be a bad 
> conductor (does this fall into the definition of semimetal???)
> Flat bands give high DOS? Not always, for example NaCl at the bottom of the 
> conduction band, the band is flat and DOS is very low
> And I do not think I need a high density of k points
>
> On the other hand the f orbitals have flat bands and DO HAVE high DOS
>
> ________________________________
> De: Wien <[email protected]> en nombre de Fecher, 
> Gerhard <[email protected]>
> Enviado: martes, 29 de enero de 2019 03:49 a. m.
> Para: A Mailing list for WIEN2k users
> Asunto: Re: [Wien] Metal or semimetal
>
> I strongly disagree,
> a semi-metal (not to be confused with a half-metall) is a material that is 
> insulating (semiconducting) in one direction and conducting in another one, a 
> typical example is graphite.
> (this has nothing to do whether the bands are flat or not;
> and just to mention, the density of states is HIGH when the bands are FLAT.)
>
> The question is: What is slightly below ?
>
> If you have one (or more) partially filled band(s) that is(are) crossing the 
> Fermi energy, then you have a metal.
> (You find the occupation of the bands e.g.: in case.scf2)
>
> If you have not enough k-points (or some other bad conditions), then the 
> integration of the density of states might be bad
> and the Fermi energy may fall into the valence or conduction band (probably 
> few meV or less) even though the material is an insulator,
> this can be healed in most cases by increasing the number of k-points.
>
> In some cases you have to check whether there might be an overlapp of the 
> valence and and conduction bands at different k-points, resulting in a 
> semimetallic or zero-bandgap type behavior.
> For example you may have a large gap at Gamma with EF at the top of the 
> valence band and a large gap at another k-point, say X, with EF at the bottom 
> of the conduction band.
>
> PS.: To complete; in a half-metal one spin channel (e.g. minority) is 
> insulating (semiconducting) and the other spin channel is metallic (e.g.: 
> majority)
>
>
>
> Ciao
> Gerhard
>
> DEEP THOUGHT in D. Adams; Hitchhikers Guide to the Galaxy:
> "I think the problem, to be quite honest with you,
> is that you have never actually known what the question is."
>
> ====================================
> Dr. Gerhard H. Fecher
> Institut of Inorganic and Analytical Chemistry
> Johannes Gutenberg - University
> 55099 Mainz
> and
> Max Planck Institute for Chemical Physics of Solids
> 01187 Dresden
> ________________________________________
> Von: Wien [[email protected]] im Auftrag von delamora 
> [[email protected]]
> Gesendet: Freitag, 25. Januar 2019 01:53
> An: A Mailing list for WIEN2k users
> Betreff: Re: [Wien] Metal or semimetal
>
> If Ef is near the edge of a band, close to the bandgap then it would be a bad 
> conductor, since the bands would be quite flat (and the velocity of the 
> electrons is proportional to the slope of the band) and the DOS would be low, 
> so I would call it a semimetal
>
>
> ________________________________
>
> Dear wien2k users:
>
> I have a question that does not have any relation with wien2k but I would be 
> grateful if you can answer me or send me a document:
>
> When the fermi level passes slightly below the top of the valance band with 
> the presence of a wide gap, this indicates a metal or semimetalic behavior.?
>
> Thank you in advance
> _______________________________________________
> Wien mailing list
> [email protected]
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