https://bugzilla.wikimedia.org/show_bug.cgi?id=51180
Web browser: --- Bug ID: 51180 Summary: AbuseFilter's API do not return the filter id (but returns its name) for private filters Product: MediaWiki extensions Version: unspecified Hardware: All OS: All Status: NEW Severity: normal Priority: Unprioritized Component: AbuseFilter Assignee: wikibugs-l@lists.wikimedia.org Reporter: mybugs.m...@gmail.com CC: agarr...@wikimedia.org, nischay...@gmail.com Classification: Unclassified Mobile Platform: --- In a query like https://pt.wikipedia.org/w/api.php?action=query&format=jsonfm&list=abuselog&aflfilter=14&afllimit=1&aflprop=ids|filter&afldir=newer I get a result such as this: { "query-continue": { "abuselog": { "aflstart": "2009-06-25T18:01:56Z" } }, "query": { "abuselog": [ { "id": 26323, "filter_id": "", "filter": "Conte\u00fado de texto como propaganda" } ] } } If the query can provide the filter description (in the "filter" property) it should also show the filter number (in the "filter_id" property). I see no reason to provide one of these but not the other for private filters. -- You are receiving this mail because: You are the assignee for the bug. You are on the CC list for the bug. _______________________________________________ Wikibugs-l mailing list Wikibugs-l@lists.wikimedia.org https://lists.wikimedia.org/mailman/listinfo/wikibugs-l