On 18 Jul 2003, Mike Hearn wrote: > Hm, so if you declare an array like so: > > DWORD args[32]; > > and then pass args as a parameter of type "DWORD *args", it > automatically gets the address of it? I thought passing variables > directly like that would normally cause a copy by value, but I don't > know C well enough I suppose.
Yes, in C everything is passed by value, but args is a pointer to 32 consecutive DWORDs, so in this case the value of args is the address, and it's the address that gets copied. -- Dimi.