Hi,
I got the follow error when I tried to compile your example:
teste3.x10:4: The argument, row, should be of type region(:rank==1) instead of
x10.lang.region.
teste3.x10:6: Method point(int[]) in x10.lang.point.factory cannot be called
with arguments (int(:self=1), x10.lang.region).
The source is:
public class teste3 {
public static void main(String args[]) {
region row = [0:7];
dist D = dist.factory.block([0:1, row]);
final double[.] darr = new double[D];
finish ateach (point p : D | ([1, row])) {
darr[p] = here.id;
}
}
}
Could you help me?
Thanks,
Eduardo
On Dec 11, 2007 11:41 AM, Igor Peshansky <[EMAIL PROTECTED]> wrote:
> "Eduardo Rocha" <[EMAIL PROTECTED]> wrote on 12/11/2007 08:26:31 AM:
>
>
> > Hi,
> >
> > I would like to know how to iterate over a single row or column of a
> > X10 matrix. For instance, I have the follow matrix:
> >
> > dist D = dist.factory.block([0:1, 0:7]);
> > final double[.] darr = new double[D];
> >
> > and I want to interact over the second row. How can I do that? The
> > next code interact over the entire matrix. How can I change it to
> > interact only over the second row:
> >
> > finish ateach(point p: darr) {
> > darr[p] = here.id;
> > }
> >
> > Thanks in advance,
> > Eduardo
>
> Hi, Eduardo,
>
> You can use
>
> region row = [0:7];
> dist D = dist.factory.block([0:1, row]);
> final double[.] darr = new double[D];
> finish ateach (point p : D | ([1, row])) {
> darr[p] = here.id;
> }
>
> In other words, you don't have to iterate over the whole distribution.
> The above is the simplest way I know to get the right points in the
> right places for a block distribution.
> Igor
> --
> Igor Peshansky (note the spelling change!)
> IBM T.J. Watson Research Center
> XJ: No More Pain for XML's Gain (http://www.research.ibm.com/xj/)
> X10: Parallel Productivity and Performance (http://x10.sf.net/)
>
>
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