On Aug 27, 2009, at 3:55 PM, Igor Peshansky wrote:
> You can also use the place-local idiom, as follows:
>
> val norms = Array.make[Double](Dist.makeUnique(), (Point)=>0.0);
> finish ateach ( (p) in distS.places() ) {
> for ( (i, j) in distS | p ) { // at this point, p == here
> norms(p.id) += Math.sqrt(S(i,j).real*S(i,j).real +
> S(i,j).image*S(i,j).image);
> }
> }
> rawNormPower2 = norms.sum(); // a distributed reduction
>
> Here, norms is an array with a unique distribution (which has one
> point
> per place). The ateach loop again spawns parallel iterations on each
> place (but now there's one per place covered by the distribution).
> The
> body of the ateach has a sequential loop that runs over the part of
> distS
> that lives in that place. Each iteration of that sequential loop
> updates
> the local element of norms. There is no need for atomic, since all
> updates happen sequentially. Once the ateach loop is done, a
> (distributed)
> reduction is performed over the norms array, and the sum is stored
> in the
> final result location.
Using this method and Java backend, I have
rawNormPower2 = 0;
val norms = Array.make[Double](Dist.makeUnique(), (Point)=>0.0);
finish ateach( (p) in distS.places() ){ //line 327
for( (i,j) in distS | p ){
norms(p.id) += Math.sqrt(S(i1,j1).real*S(i1,j1).real +
S(i1,j1).image*S(i1,j1).image);
}
}
rawNormPower2 = norms.sum()/( N*Mc ); //line 333
but get this
/Users/jlagrone/GradSchool/Research/workspace/X10-code/SSCA3-X10/src-
par/State.x10:327: Could not infer type for formal parameter.
/Users/jlagrone/GradSchool/Research/workspace/X10-code/SSCA3-X10/src-
par/State.x10:327: Could not infer type for formal parameter.
/Users/jlagrone/GradSchool/Research/workspace/X10-code/SSCA3-X10/src-
par/State.x10:333: No valid method call found for sum() in
x10.lang.Array[x10.lang.Double].
Also, is it safe to assume this will work with Java backend on dual-
core machine? Or should I do development on cluster from here on out?
How should the program be executed. We usually use slurm, but is there
some special method?
Jim
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