Hi,
I am currently playing with implicit clock syntax, and even with simple
programs, I am seeing some unexpected behavior that I cannot explain. I did a
quick search on the past emails, and found some bug reports/fixes, but I didn't
find anything that matches what I have.
The following code is supposed to be completely deterministic due to clocks,
and I expect the output to be x=0. However, it always gives x=1.
import x10.io.Console;
class Test3 {
public static def main(Rail[String]) {
var x: Long = -1;
clocked finish {
clocked async {
Clock.advanceAll();
x= 1;
Clock.advanceAll();
}
clocked async {
Clock.advanceAll();
Clock.advanceAll();
x= 0;
}
Clock.advanceAll();
}
Console.OUT.println("x="+x);
}
}
x10c Test3.x10; x10 Test3
x=1
Now, if I remove the last call to advanceAll (Test4, code is at bottom of
mail), I get x=-1.
$x10c Test4.x10; x10 Test4
x=-1
My expected value is x=0. I cannot see why removing the last call to advance
alters the behavior. If someone have any idea about this behavior, I would
appreciate your input.
Thank you,
Tomofumi Yuki
===Some detailed info===
I am using OSX 10.9.5
$x10c -version
x10c version 2.5.0
$java -version
java version "1.8.0_25"
Java(TM) SE Runtime Environment (build 1.8.0_25-b17)
Java HotSpot(TM) 64-Bit Server VM (build 25.25-b02, mixed mode)
import x10.io.Console;
class Test4 {
public static def main(Rail[String]) {
var x: Long = -1;
clocked finish {
clocked async {
Clock.advanceAll();
x= 1;
Clock.advanceAll();
}
clocked async {
Clock.advanceAll();
Clock.advanceAll();
x= 0;
}
}
Console.OUT.println("x="+x);
}
}
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