PLEASE DO NOT REPLY TO THIS MESSAGE. TO FURTHER COMMENT ON THE STATUS OF THIS BUG PLEASE FOLLOW THE LINK BELOW AND USE THE ON-LINE APPLICATION. REPLYING TO THIS MESSAGE DOES NOT UPDATE THE DATABASE, AND SO YOUR COMMENT WILL BE LOST SOMEWHERE. http://nagoya.apache.org/bugzilla/show_bug.cgi?id=2835 *** shadow/2835 Thu Jul 26 08:28:48 2001 --- shadow/2835.tmp.17149 Thu Jul 26 08:34:49 2001 *************** *** 79,82 **** If you need more information, mail me. ! Regards, Joerg Heinicke --- 79,90 ---- If you need more information, mail me. ! Regards, Joerg Heinicke ! ! ------- Additional Comments From [EMAIL PROTECTED] 2001-07-26 08:34 ------- ! In your second example, I think you have the "name" and "select" attributes of ! your xsl:param element switched. Also, the value needs to be in apostrophes. ! Otherwise, it is interpreted as an XPath. ! ! In your first example, you get the exception because the value of the parameter ! is not set. How are you trying to pass in the value of the parameter?
