XSLT requires that the patterns in the match attribute be namespace qualified.
Try: <xsl:template match="/d:FOO" xmlns:d="http://www.foo.org/";> HTH, Gary > -----Original Message----- > From: Robert Zimmermann [mailto:[EMAIL PROTECTED] > Sent: Friday, November 28, 2003 9:43 AM > To: [EMAIL PROTECTED] > Subject: XalanC: transform xml wich is in an default-namespace > > > Hi, > > I have an xml-source wich defines an default namespace in > it's root element: > > test.xml > > <?xml version="1.0" encoding="utf-8"?> > <FOO xmlns="http://www.foo.org/";> > <TEXT>some text here</TEXT> > </FOO> > > and try to transform it with this simple stylesheet: > > test.xsl > > <?xml version="1.0" encoding="utf-8"?> > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform";> > > <xsl:template match="/FOO"> > <xsl:text>Yes It Works</xsl:text> > </xsl:template> > > </xsl:stylesheet> > > > but my template never get called, insted the default-templates run. > > is this a bug, or did i miss something in xslt? > > My Components are: > xalan 1.5 > xerces 2.2.0 > > thanks, > robert >
