[ http://issues.apache.org/jira/browse/XALANJ-1043?page=all ]
Brian Minchau updated XALANJ-1043:
----------------------------------
Version: 2.4
(was: Latest Development Code)
> Iusses with Encoder and Tomcat 4.0.3
> ------------------------------------
>
> Key: XALANJ-1043
> URL: http://issues.apache.org/jira/browse/XALANJ-1043
> Project: XalanJ2
> Type: Bug
> Components: Serialization
> Versions: 2.4
> Environment: Operating System: Windows NT/2K
> Platform: PC
> Reporter: Bryan Kearney
> Assignee: Xalan Developers Mailing List
>
> I attempted to use the nightly build of Xalan from 5/22/2002 within Tomcat
> 4.0.3. I have unjarred build into a web-app. I got a null point ecxception on
> line 357 of org.apache.xalan.serialized.Encodings.java. I believe the issue is
> how the Encodings.java is located within tomcats nested class loaders.
> I debugged a little bit and modified the code, and this is what I saw (See the
> System.outs)
> "ST" was blank
> "BK" showed a tomcat WebAppClass loader which pointed to the WEB-INF\classes
> directory as it should. It delegeted up several layers as is typical for
> tomcat.
> "B" was null
> "C" was null
> by moving the location of the file, it was found. TO be fair.. I do not recall
> if it ws "B" or "C" that found it however.
> private static EncodingInfo[] loadEncodingInfo()
> {
> URL url = null;
> try {
> String urlString =
> System.getProperty("org.apache.xalan.serialize.encodings", "");
> System.out.println("ST" + urlString) ;
> if (urlString == null || urlString.length() == 0) {
> ClassLoader cl = Encodings.class.getClassLoader();
> System.out.println("org/apache/xalan/serialize/" +
> ENCODINGS_FILE) ;
> System.out.println("BK" + cl) ;
> if (cl == null) {
> url = ClassLoader.getSystemResource("org/apache/xalan/serialize/" +
> ENCODINGS_FILE);
> System.out.println("A" + url) ;
> } else {
> url = cl.getResource(ENCODINGS_FILE);
> System.out.println("B" + url) ;
> if (url == null)
> url = ClassLoader.getSystemResource("org/apache/xalan/serialize/"
> +
> ENCODINGS_FILE);
> System.out.println("C" + url) ;
> }
> } else {
> url = new URL (urlString);
> System.out.println("D" + url) ;
> }
> // ? consider whether we should allow an exception here if resource
> // is not found or should we return an empty array ?
> InputStream is = url.openStream();
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