Hi Zak,
This may not be the answer you're looking for, but if you have to transform XML and you want to use Java, I think you'll be much happier using JPlates (http://www.jplates.com) than Xalan. I think XSLT is fine until your XML actually *means* something that you can't express in an XSD, and then you need something that gives you a real object-oriented template programming model, and immediate access to all of Java.
All the best, -- Dan Jacobs
[EMAIL PROTECTED] wrote:
Another question about XSLTC java extension functions:
I'd like to use an java ext function with a Boolean parameter, like public static Boolean testBoolean(Boolean bool);
I tried to call this function using <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; xmlns:TestClass="xalan://TestClass"> ... <xsl:when test="TestClass:testBoolean(true)"/>
But I got the following error message while trying to compile the stylesheet to translets:
Compiler error(s):
Cannot convert argument/return type in call to method 'TestClass.testBoolean(node-set)'
Error checking type of the expression 'cast(funcall(xalan://TestClass:testBoolean, [step("child", 8)]), boolean)'.
I tried boolean and Boolean in all possible combinations, but no luck. Using a NodeList parameter in Java helps, but I only get an empty NodeList in the java function.
This xsl/class combo works fine with regular Xalan. Is boolean supported in XSLTC? Are there workarounds?
Thanks for any help, zak :-)
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