> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
> version="1.0">
>
> <xsl:output method="xml"/>
> <xsl:strip-space elements="*"/>
> <xsl:preserve-space elements="xhtml:*"
> xmlns:xhtml="http://www.w3.org/1999/xhtml"/>
>
> <xsl:template match="*">
> <xsl:copy>
> <xsl:for-each select="@*">
> <xsl:copy-of select="."/>
> </xsl:for-each>
> <xsl:apply-templates/>
> </xsl:copy>
> </xsl:template>
> </xsl:stylesheet>
>
> You would expect to get effectively that same stylesheet back out,
however
> what actually comes out is the same stylesheet minux the xmlns:xhtml
> declaration which then causes errors when attempting to use it as a
> stylesheet (except with XSLTC which seems to ignore xsl:preserve-space).
>
> If I change the template to be just:
>
> <xsl:template match="*">
> <xsl:copy-of select="."/>
> </xsl:template>
>
> the xmlns:xhtml declaration is preserved. I would have thought the two
> constructs were equivalent though.
They are not equivalent. This is a generic XSLT question, so a better
forum for it would be the Mulberry XSL list. However, a few pointers:
1. Namespace nodes are not attributes in the XPath data model:
http://www.w3.org/TR/xpath#data-model
2. You should take a look at the copy instruction in XSLT for more
information. There is even an example of the canonical identity
transformation stylesheet:
http://www.w3.org/TR/xslt#copying
Dave
