Am 11.03.2011 09:58, schrieb Jan Kiszka:
On 2011-03-11 09:51, Gilles Chanteperdrix wrote:
Johann Obermayr wrote:
void task_waiter_do(void *data)
{
rt_printf("task_waiter_do started\n");
while(task_waiter_flag == 0)
; // rt_task_sleep( DELAYMS(1) );
rt_printf("task_waiter_do finished\n");
}
What happens if you uncomment the rt_task_sleep here ?
Given how often users make this mistake, should we enable the watchdog
by default?
Jan
We have a watchdog, and your watchdod-task suspend the user-task
(task_waiter_do).
the sample show this problem.
The task_worker_do is a watchdog. he control some other 'user-task'.
In your project, the watchdog startup the watchdog-task.
the task_worker_do suspend the user-task.
the task_worker_do will delete the user-task.
if the user-task have only while(1); than the machine will hang.
if the user-task have in the while a sleep or other function,
the task_worker_do can delete the task_waiter, and all work correct.
Jimmy
--
Mit freundlichen Grüßen, best regards
Johann Obermayr
Software Entwicklung
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