On 21.12.18 14:44, Henning Schild via Xenomai wrote:
From: Henning Schild <henning.sch...@siemens.com>

We should mark the current task as not owning the fpu anymore if it does
actually own the fpu, not if the fpu itself is active.

Fixes cb52e6c7438fa

Reported-by: Mauro Salvini <mauro.salv...@smigroup.net>
Signed-off-by: Henning Schild <henning.sch...@siemens.com>
---
  kernel/cobalt/arch/x86/thread.c | 2 +-
  1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/kernel/cobalt/arch/x86/thread.c b/kernel/cobalt/arch/x86/thread.c
index a09560075..0c6054338 100644
--- a/kernel/cobalt/arch/x86/thread.c
+++ b/kernel/cobalt/arch/x86/thread.c
@@ -475,7 +475,7 @@ void xnarch_leave_root(struct xnthread *root)
        switch_fpu_finish(&current->thread.fpu, smp_processor_id());
  #else
        /* mark current thread as not owning the FPU anymore */
-       if (&current->thread.fpu.fpstate_active)
+       if (&current->thread.fpu.fpregs_active)

Well, if you had used fpregs_active() here, you would have resolved also the second bug of that line (which I only spotted now):
"if (&something)" is always true...

Jan

                fpregs_deactivate(&current->thread.fpu);
  #endif
  }


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