On Thu, 21 Jun 2001, Martin Farrell wrote:
> I have a method that will create an xml output (a.toXML()) as a String. Now
> my problem is that I would like to parse this String directly, and reduce
> the overhead of file creation in my application
Create a parser instance, set up the appropriate features and then call:
parser.parse(new InputSource(new StringReader(a.toXML())));
Ian
--
Ian Roberts, Software Engineer DecisionSoft Ltd.
Telephone: +44-1865-203192 http://www.decisionsoft.com
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